Q3: Preview BONUS: In this class, and in the MATH 144 notes, we defined the inverse secant function as y = sec (x) sec y = X, for y E [0, 7/2) U [ T, 35/2). With this choice of principal branch the derivative of sec (x) is d dx sec (x) *Vx2 - 1 However, as mentioned in the side remark in Section 4.9, there is another common definition of sec (x), which is y = sec (x) sec y - x, for y E [O, T/2) U (7/2, z] For instance, this is the definition considered in the CLP textbook. Show that, with this choice of principal branch to define the inverse secant function, its derivative becomes d sec (x) dx