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Q4. The reaction X(g) + Y(s) 22(g) has Kp=2.35 at 690 K. What is the mole fraction of X at equilibrium when 0.08 mole of

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Q4. The reaction X(g) + Y(s) 22(g) has Kp=2.35 at 690 K. What is the mole fraction of X at equilibrium when 0.08 mole of X and 0.12 mole of Y are placed on 2 L of container and allowed to reached the equilibrium at 690 K

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