Question
Q4. Write a function named 'printEvens' that accepts 2 integers 'a' and 'b' and creates and returns an array such that all numbers between a
Q4. Write a function named 'printEvens' that accepts 2 integers 'a' and 'b' and
creates and returns an array such that all numbers between a and b (inclusive) contain
only even digits (0 is considered even)!
For example, printEvens(433, 452) would create and return a new list with the following
values: [440, 442, 444, 446, 448]
NOTE: EACH and EVERY digit MUST be an EVEN number, NOT simply that the entire
number itself be EVEN!
import math
import random
import string
import collections
import datetime
import re
import time
import copy
# YOUR CODE BELOW...
def checkRegex(str2) :
your code here...
# end def
def fancyList(table, cityFrom, cityTo) :
your code here...
# end def
def natureSequence(fn, sn, n) :
your code here...
# end def
def printEvens(a, b) :
your code here...
# end def
def generatePokerHand(deck, coords) :
your code here...
# end def
def main( ) :
rv = checkRegex("abcdefghijklmnopqrstuvwxyz")
print(rv)
rv = checkRegex("Mariner!")
print(rv)
rv = checkRegex("acdefGhij*012345")
print(rv)
fancyList( )
rv = natureSequence(0, 1, 10)
rv = natureSequence(1, 3, 15)
printEvens(433, 452)
printEvens(2048, 2188)
deck = [["2C", "3C", "4C", "5C", "6C", "7C", "8C", "9C", "XC", "JC", "QC", "KC","AC"],
["2D", "3D", "4D", "5D", "6D", "7D", "8D", "9D", "XD", "JD", "QD", "KD", "AD"],
["2H", "3H", "4H", "5H", "6H", "7H", "8H", "9H", "XH", "JH", "QH", "KH", "AH"],
["2S", "3S", "4S", "5S", "6S", "7S", "8S", "9S", "XS", "JS", "QS", "KS", "AS"]
]
coords=["22", "0A", "38", "1B", "25"]
rv = generatePokerHand(deck, coords)
coords=["23", "24", "25", "26", "27"]
rv = generatePokerHand(deck, coords)
# end main( )
if __name__ == "__main__" :
main( )
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