Quality control personnel at a pharmacuetical factory are checking for deviations in the correct amount of the active ingredient in 5mg pills. The average amount of active ingredient in all pills of this type is supposed to be 10 micrograms. The sample of 100 pills has mean 9.97 micrograms and standard deviation 3 micrograms. Their hypotheses are Ho: mu = 10 versus Ha: mu NE 10. Their p-value turns out to be 0.921. What is their conclusion?

Since the p-value exceeds 0.2, they have no evidence that the average amount of active ingredient in all pills of this type is smaller than 10 micrograms.

Since the p-value exceeds 0.05, they can claim that the average amount of active ingredient in all pills of this type is not 10 micrograms

Since the p-value exceeds 0.2, they have evidence that the average amount of active ingredient in all pills of this type is 10 micrograms.

Since the p-value exceeds 0.05, they can claim that the average amount of active ingredient in all pills of this type is 10 micrograms

Since the p-value exceeds 0.2, they have no evidence that the average amount of active ingredient in all pills of this type is bigger than 10 micrograms.

Since the p-value exceeds 0.2, they have no evidence that the average amount of active ingredient in all pills of this type is different from 10 micrograms.