Question
Question 1 (1 point) Question 1 options: The population standard deviation for the height of college football players is 3.3 inches. If we want to
Question 1 (1 point)
Question 1 options:
The population standard deviation for the height of college football players is 3.3 inches. If we want to estimate a 90% confidence interval for the population mean height of these players with a 0.7 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:
Question 2 (1 point)
Question 2 options:
The population standard deviation for the height of college hockey players is 3.4 inches. If we want to estimate 90% confidence interval for the population mean height of these players with a 0.6 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:
Question 3 (1 point)
Question 3 options:
The population standard deviation for the height of college basketball players is 3.4 inches. If we want to estimate 95% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:
Question 4 (1 point)
Question 4 options:
There is no prior information about the proportion of Americans who support gun control in 2018. If we want to estimate 95% confidence interval for the true proportion of Americans who support gun control in 2018 with a 0.36 margin of error, how many randomly selected Americans must be surveyed? Answer: (Round up your answer to nearest whole number)
Question 5 (1 point)
Question 5 options:
The population standard deviation for the height of college basketball players is 3 inches. If we want to estimate a 99% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer:
Question 6 (1 point)
Question 6 options:
There is no prior information about the proportion of Americans who support Medicare-for-all in 2019. If we want to estimate 95% confidence interval for the true proportion of Americans who support Medicare-for-all in 2019 with a 0.3 margin of error, how many randomly selected Americans must be surveyed? Answer: (Round up your answer to nearest whole number)
Question 7 (1 point)
Question 7 options:
A researcher would like to estimate the proportion of all children that have been diagnosed with Autism Spectrum Disorder (ASD) in their county. They are using 95% confidence level and the CDC national estimate that 1 in 68 0.0147 children are diagnosed with ASD. What sample size should the researcher use to get a margin of error to be within 2%? Round up to the nearest integer. Answer
Question 8 (1 point)
Question 8 options:
A teacher wanted to estimate the proportion of students who take notes in her class. She used data from a random sample of size n = 82 and found that 50 of them took notes. The 99% confidence interval for the proportion of student that take notes is:
< p <
. Round answers to 3 decimal places.
Question 9 (1 point)
Question 9 options:
In a random sample of 80 people, 52 consider themselves as baseball fans. Compute a 95% confidence interval for the true proportion of people consider themselves as baseball fans and fill in the blanks appropriately. We are 95% confident that the true proportion of people consider themselves as baseball fans is between
and
. (round to 3 decimal places)
Question 10 (1 point)
Question 10 options:
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.42 based on a random sample of 100 customers. Compute a 92% confidence interval for the true proportion of customers who click on ads on their smartphones and fill in the blanks appropriately.
< p <
(round to 3 decimal places)
Question 11 (1 point)
From a sample of 500 items, 30 were found to be defective. The point estimate of the population proportion defective will be:
Question 11 options:
0.06 | ||||||||||||||||||||||||||||||||||||||||||||||
0.60 | ||||||||||||||||||||||||||||||||||||||||||||||
0.94 | ||||||||||||||||||||||||||||||||||||||||||||||
30 Question 12 (1 point) The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking samples of sizes n = 160 units. Suppose that today's sample contains 14 defectives. How many units would have to be sampled to be 95% confident that you can estimate the fraction of defective parts within 2% (using the information from today's sample--that is using the result that p^=0.0875 Place your answer, as a whole number, in the blank. For example 567 would be a legitimate entry. ___ ___ Question 12 options:
|
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started