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Question 1 1 pts abc is an isosceles right-triangle prism in air. An incident ray is perpendicular to the ab side. The transmitted ray from
Question 1 1 pts abc is an isosceles right-triangle prism in air. An incident ray is perpendicular to the ab side. The transmitted ray from the back side (bc) has an angle of a = 150 with the direction of the incident ray. What is the index of refraction of the prism? 45 CMedium 1 (n1= 1.2) and medium 2 (n2= 1.8) are two rectangular-shaped layers stacking together. An incident ray in medium 2 makes a right triangle with AB and BC; AB is the normal direction to the interface. If the height of AB is h = 1 m, what distance of BC will result in total internal reflection at the interface? medium 1 iA medium 2 B C\fA thin layer of SiO, having an index of refraction 1.5, is used as coating on certain solar cells. The refraction index of the solar cell is 3.5. The thickness of the SiO layer is D = 200 nm. If a visible beam with wavelength 2 (in air) has constructive interference when reflected from the top of the SiO layer, which of the following value can be the wavelength 1? Visible light spectrum is from 380 to 730 nm. 1 nm =1x10 9 m. air D Sio solar cell 500 nm 400 nm 460 nm 600 nm 540 nm 300You pass 633-nm laser beam through a narrow slit and observe the diffraction pattern on a screen 6 m away. If the slit width is 3x104 m, what is the distance between the first-order and the fifth-order dark fringe on the screen? Only consider dark fringes on one side of the central bright fringe. 1 cm = 1x102 m. O 2 cm 16 cm 5 cm 9 cm O 7 cm 22 cmA light source emits two wavelengths: 400 nm and 600 nm. A researcher shines the light source on a double-slit apparatus with a slit separation of 2.5x10-5 m. The diffraction pattern is observed on a screen 5 m away from the slit. What is the separation distance between the third-order bright fringes for the two wavelengths? 1 cm = 1x10-2 m. 1 nm =1x10 9 m. O 12 cm 10 cm O 6 cm O 8 cm 1 cm O 4 cm
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