Question 1 1 pts

How many iterations of the for loop does this program perform?

int main(void) { int a[] = {1, 2, 3, 4}; int i; for (i = 0; i < 4; i++) { if (a[i] < 0) return 1; else return 0; } return 0; }

	Four.
	One.

	No iterations.
	The program crashes.

The program does not compile.

Question 2 1 pts

What does the following program do?

int main(void) { int i, a[]; a[0]=1; for (i=0; i<10; i++) { a[i] = a[i-1] + 2*i + 1; } return 0; }

	It fills the array with the squares of the integers from 1 to 10.
	It does not compile.

	It crashes when it is run because no memory is reserved for the array.
	It fills the array with the first 10 powers of 2.

Question 3 1 pts

What's the problem with this code?

int main(void) { int i, a[5]; for (i=1; i <= 5; i++) { a[i] = i+1; } return 0; }

	It doesn't compile because one cannot declare an int variable and an int array on the same line.
	There is no problem. The code will run just fine.

	The main problem is that the loop accesses a non-existing a[5]. This will cause some memory location to be inadvertently written. The secondary problem is that a[0] is left uninitialized.
	It crashes because a[1] is accessed before a[0].

Question 4 1 pts

If a is declared with

int a[10];

what value does sizeof(a) have?

	10*sizeof(int)
	Whatever is the size of a pointer to an integer.

	10
	14

Question 5 1 pts

What does the following program do?

#include int main(void) { int a[] = {1,2,3,4}; int b[4]; b = a; printf("%4d ", b); return 0; }

	It does not compile. You cannot copy arrays like that.
	It prints 1 2 3 4.

	The program incurs a segmentation fault when run.
	It does not compile. You cannot print an entire array like that.

Question 6 1 pts

Arrays are just pointers in disguise.

	True
	False

Question 7 1 pts

Declaring too large an array in a function may cause a stack overflow when the function is called.

	True
	False

Question 8 1 pts

What does the following program do?

int main(void) { int a[4]; a = {1,2,3,4}; return a[3]; }

	It crashes because main can only return 0.
	It does not compile.

	It returns 4.
	It returns 3.

Question 9 1 pts

What does the following program do?

#include int main(void) { int i = 2; int a[] = {0,1,2,3,4}; int n = sizeof(a) / sizeof(a[0]); for (i = 0; i < n; i++) { (*(a+i))++; printf(" %d", a[i]); } printf(" "); return 0; }

	It does not compile.
	It prints: 1 1 1 1 1

	It crashes because it causes a segmentation fault.
	Prints: 1 2 3 4 5.

Question 10 1 pts

What does the following program do?

#include int main(void) { int * p; int a[] = {0,1,2,3,4}; int n = sizeof(a) / sizeof(a[0]); for (p = a; p != a+n; p++) { printf(" %d", *p); } printf(" "); return 0; }

	It doesn't compile. You cannot assign an array to a pointer because they are of different types.
	It prints: 0 1 2 3 4

	It crashes because p != a+n accesses an address that is out of bounds.
	It prints nonsense because %d is for integers, while p is a pointer.

Four.