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QUESTION 1 (20 Marks) A[[n]]sA[[x]]sA[[a1+a2]]sA[[a1a2]]sA[[a1a2]]s=N[[n]]=sx=A[[a1]]s+A[[a2]]s=A[[a1]]sA[[a2]]s=A[[a1]]sA[[a2]]s i. Solve when sx=3 for the A[[x+1]]s ii. Solve when sx=9 for the A[[x+8]]s iii. Solve when s=1,x=3 for the
QUESTION 1 (20 Marks) A[[n]]sA[[x]]sA[[a1+a2]]sA[[a1a2]]sA[[a1a2]]s=N[[n]]=sx=A[[a1]]s+A[[a2]]s=A[[a1]]sA[[a2]]s=A[[a1]]sA[[a2]]s i. Solve when sx=3 for the A[[x+1]]s ii. Solve when sx=9 for the A[[x+8]]s iii. Solve when s=1,x=3 for the A[[(x+7)(x3)]]s+A[[(x+2)(x+5)]]s (20 marks)
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