Question 1: (20 marks) Answer the following questions related to VLSM (20 marks) The network administrator...
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Question 1: (20 marks) Answer the following questions related to VLSM (20 marks) The network administrator has set up the network topology for the ELC Company. The details of the topology of the network are as follows: Visitor: can accommodate up to 65 Laptops/tablets/smart phones connected to 2 access points*. Accounting: has 3 PCs, 3 VoIP phones, 1 server, and 2 network printers connected to 1 switch*. Support: has 5 PCs connected to 3 access points*. Employee: has 18 PCs, 18 VoIP phones, and 2 network printer connected to 2 switches*. Marketing: has 4 PCs, 4 VoIP phones, and 2 servers connected to 1 switch*. WAN: routers R1 and R2 are connected using serial ports. *Switches and access point(s) should be accessible remotely (an IP address should be assigned for the switch/access point). A) Determine the number of hosts for each of the six networks? (7 marks) Show the steps you followed to obtain the number of hosts B) Determine the number of prefix for each network (7 marks) Show the steps you followed to obtain the prefix of the first LAN (Admin) or any other LAN. C) Subnet the address block 140.20.5.0/24 as appropriate to provide an efficient use of the addresses but at the same time providing sufficient addresses for all groups and links. (6 marks) (Present your answer in a table similar to table 1) Network name Table 1 Network/subnet address Address Range Broadcast address Prefix/mask Analyze and identify the types of the buses shown in the figure from its specifications. [5 marks] All the values given in the table are admittance values in mho. Choose 250MVA and X KV as base and apply PU calculation to examine all the admittances in PU. And finally show the bus admittance matrix of the network. [5 marks] (ii) Using suitable method, deduce the expressions for unknown parameters of each bus and estimate the values for all the unknown parameters up to 3rd iteration. [5 marks] (iv) Analyze the estimated values of the parameters of third iteration and judge the condition of the load bus. [5 marks] **** Where x indicates base voltage, which will be determined from middle part of your ID. If your ID is 15-25634-2 then base voltage will be 25.634KV. MY ID:17-40745-3 Line Admittance (1) 1-2 0.5+1.0 1-3 0.20+0.8 1-4 0.30+j 1.2 2-3 0.25 +0.8 3-4 0.15+0.6 1 <0 pu 300 MW 50 MVA 138 MW 45.2 MVA 260 MW 105 MVA Consider the network diagram in Figure 1 and answer the following questions. Further, the IP address are for illustrative purposes only. Use your own IP addressing scheme (You may use class full and classless IP addresses as per your preference). Note that students need to attach the screenshot(s) of their topology and configurations in their answer sheet. 203.20.10.25/18 (0400) Router A Router B 200.12.10.20/18 172.16.1.2/16 172.16.1.1/16 192.168.20.1/24 172.16.10.100/16 192.168.20.200/24 10.10.1.1/8 10.10.1.100/8 Host B Host A 172.22.1.1/30 128 kbps SH R1 EO 50 172.19.2.0/24 172.22.1.5/30 64 kbps 172.22.2.1/30 172.22.1.6/30 R3 R2 Loopback: 172.16.1.1 Loopback: 172.20.1.1 172.18.1.0/24 172.17.1.0/24 a) Configure OSPF on R1. Start your work from the global configuration (4 marks) mode. Write down the correct command prompt in your answer. b) What is/are the Neighbor ID(s) of R1? c) The routers in the below network are running OSPF. (2 marks) BranchA Fa0/0 192.168.3.1 swech Fa0/0 192.168.1.2 Fa0/0 192.168.3.3 BranchC Part 4: Long-answer questions (10 points each) 1. The following graph is a topology of a network, (u, v, w, x, y, z) are the routers, the edges are the links, and the weights on edges are the costs. Please use the Dijkstra's algorithm to determine the least cost path between u and z. Document your progress in the step-wise table, where N' records the set of nodes whose least cost path definitively known, D(v) records the current value of cost of path from source to v, p(v) records the predecessor node along path from source to v. 7 5 3 8 3 2 Step N' D(v) D(w) D(x) D(y) D(z) p(v) p(w) p(x) p(y) p(z) Finally, the least cost path between u and z is: u, W, V, 4,2 Question 1: (20 marks) Answer the following questions related to VLSM (20 marks) The network administrator has set up the network topology for the ELC Company. The details of the topology of the network are as follows: Visitor: can accommodate up to 65 Laptops/tablets/smart phones connected to 2 access points*. Accounting: has 3 PCs, 3 VoIP phones, 1 server, and 2 network printers connected to 1 switch*. Support: has 5 PCs connected to 3 access points*. Employee: has 18 PCs, 18 VoIP phones, and 2 network printer connected to 2 switches*. Marketing: has 4 PCs, 4 VoIP phones, and 2 servers connected to 1 switch*. WAN: routers R1 and R2 are connected using serial ports. *Switches and access point(s) should be accessible remotely (an IP address should be assigned for the switch/access point). A) Determine the number of hosts for each of the six networks? (7 marks) Show the steps you followed to obtain the number of hosts B) Determine the number of prefix for each network (7 marks) Show the steps you followed to obtain the prefix of the first LAN (Admin) or any other LAN. C) Subnet the address block 140.20.5.0/24 as appropriate to provide an efficient use of the addresses but at the same time providing sufficient addresses for all groups and links. (6 marks) (Present your answer in a table similar to table 1) Network name Table 1 Network/subnet address Address Range Broadcast address Prefix/mask Analyze and identify the types of the buses shown in the figure from its specifications. [5 marks] All the values given in the table are admittance values in mho. Choose 250MVA and X KV as base and apply PU calculation to examine all the admittances in PU. And finally show the bus admittance matrix of the network. [5 marks] (ii) Using suitable method, deduce the expressions for unknown parameters of each bus and estimate the values for all the unknown parameters up to 3rd iteration. [5 marks] (iv) Analyze the estimated values of the parameters of third iteration and judge the condition of the load bus. [5 marks] **** Where x indicates base voltage, which will be determined from middle part of your ID. If your ID is 15-25634-2 then base voltage will be 25.634KV. MY ID:17-40745-3 Line Admittance (1) 1-2 0.5+1.0 1-3 0.20+0.8 1-4 0.30+j 1.2 2-3 0.25 +0.8 3-4 0.15+0.6 1 <0 pu 300 MW 50 MVA 138 MW 45.2 MVA 260 MW 105 MVA Consider the network diagram in Figure 1 and answer the following questions. Further, the IP address are for illustrative purposes only. Use your own IP addressing scheme (You may use class full and classless IP addresses as per your preference). Note that students need to attach the screenshot(s) of their topology and configurations in their answer sheet. 203.20.10.25/18 (0400) Router A Router B 200.12.10.20/18 172.16.1.2/16 172.16.1.1/16 192.168.20.1/24 172.16.10.100/16 192.168.20.200/24 10.10.1.1/8 10.10.1.100/8 Host B Host A 172.22.1.1/30 128 kbps SH R1 EO 50 172.19.2.0/24 172.22.1.5/30 64 kbps 172.22.2.1/30 172.22.1.6/30 R3 R2 Loopback: 172.16.1.1 Loopback: 172.20.1.1 172.18.1.0/24 172.17.1.0/24 a) Configure OSPF on R1. Start your work from the global configuration (4 marks) mode. Write down the correct command prompt in your answer. b) What is/are the Neighbor ID(s) of R1? c) The routers in the below network are running OSPF. (2 marks) BranchA Fa0/0 192.168.3.1 swech Fa0/0 192.168.1.2 Fa0/0 192.168.3.3 BranchC Part 4: Long-answer questions (10 points each) 1. The following graph is a topology of a network, (u, v, w, x, y, z) are the routers, the edges are the links, and the weights on edges are the costs. Please use the Dijkstra's algorithm to determine the least cost path between u and z. Document your progress in the step-wise table, where N' records the set of nodes whose least cost path definitively known, D(v) records the current value of cost of path from source to v, p(v) records the predecessor node along path from source to v. 7 5 3 8 3 2 Step N' D(v) D(w) D(x) D(y) D(z) p(v) p(w) p(x) p(y) p(z) Finally, the least cost path between u and z is: u, W, V, 4,2
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