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Question 1 (5 + 7 + 4 + 4 +4+ 6 + 9 +4 = 43 marks) A patient weighing 73 kg received : 300

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Question 1 (5 + 7 + 4 + 4 +4+ 6 + 9 +4 = 43 marks) A patient weighing 73 kg received : 300 mg dose of drug via an IV injection. Blood samples were taken from the patient at regular intervals and the drug plasma concentration was determined for each sample (see the table below). Time (hr] cp (me/4) 0.25 11.6 0.5 8.4 0.75 7.2 1.00 5.1 1.50 4.2 2.00 3.2 3.00 19 4.00 10 6.00 0.3 (=) Using Excel ( or another graph plotting program) plot Cp versus time. Pease label the axes on your graph. (b) Using Excel (or another graph plotting program) plot In Cp versus time plot and determine the elimination rate constant for this drug. Pease label the axes on your graph. (c) Determine both the half-life (in both minutes and hours] and the volume of distribution [in both Land L/kg) for this drug. (d) The minimum therapeutically active concentration of the drug is 8.0 ug/mL. What is the duration of action of this drug? (e) If the dose of the drug was doubled, what will be the increase in its duration of action? (f) How long would it take for. 40 0%%, [ii) 80.0 %, and [ii) 99.5%% of this drug to be eliminated from the body? (g) Plot the data and estimate the clearance of the drug using the area under the curve method. (h) if 48% of the drug is excreted unchanged in the urine, determine both the renal and metabolic clearances. Question 2 (11 + 9 + 4 = 24 marks) (:) A 72 kg patient is started on a drug with an IV bolus dose of 180 mg. After 24 hours a dose of 80 mg is given, and after another 8 hours a dose of 120 my is given. Using the principle of superposition determine the concentration of the drug 3 hours after the second dose and 2 hours after the third dose. The drug has a half-life of 9.2 hours and a volume of distribution of 0.105 L/kg. Elimination of the drug can be explained using a one compartment model and first order elimination kinetics

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