Question 1 (allocating costs using ABC, product profit margin) Generic Motors Corporation has two product lines, A and B. Its contribution margin statement for last year is as follows:

	Product A	Product B	Total
sales volume (units)	150	300	450
Revenue	$15,000	$75,000	$90,000
Variable costs:
direct materials	$3,000	$15,000	$18,000
direct labor	$7,500	$30,000	$37,500
Contribution margin	$4,500	$30,000	$34,500
Fixed costs			$29,250
Profit			$5,250

Generic Motors uses ABC to allocate the fixed costs. It examined the main activities in the firm, and decided to break up the total fixed costs of $29,250 into 3 cost pools: * "labor-related" - the total cost in this pool is $7,500, allocated based on direct labor dollars * "sales-related" - the total cost in this pool is $6,750, allocated based on number of units * "production setups" - the total cost in this pool is $15,000, allocated based on the number of production batches. A is produced in batches of 10 units, and B is produced in batches of 5 units. Required: a) for each cost pool, compute the allocation rate and the amounts allocated to product A and product B. (assume that practical capacity = total activity volume for each pool) (hint: The amounts allocated to A and B from each pool should add up to the total cost in that pool. To allocate the costs in the "production setups" pool, you will have to compute the number of batches. If the total number of batches for A and B does not add up to 75, you are doing something wrong). * "labor-related" pool:

allocation rate = $ per DL$ FC allocated to A = $

FC allocated to B = $

* "sales-related" pool:

allocation rate = $ per unit

FC allocated to A = $

FC allocated to B = $

* "production setups" pool:

allocation rate = $ per batch

FC allocated to A = $

FC allocated to B = $ b) using the allocated costs from (a), compute the profit margin for product A and product B. If you get a negative number, enter it with a minus sign, i.e., enter negative $100 as -100, not ($100) profit margin for A = $

profit margin for B = $