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Question 1 Consider the following code segment: def fun ( par ) : if par 0 : return part 1 else: return fun ( par

Question 1
Consider the following code segment:
def fun(par):
if par0 :
return part 1
else:
return fun(par//2)+ fun(par//3)
x={2:3,3:2,1:2,2:1}
for i in x
z=y[0]+x[2]
for x in y :
z+=x
What will the following statement return?
fun (z)
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