Question $1$:

Consider the following equilibrium at $668K$ :

$CO(g)+C{l}_2(g)COC{l}_2(g)$

$K_p=22\mathrm{.}5$

Which of the following reaction vessels represent$($s$)$ a reaction mixture that is not at equilibrium and where the reverse direction $($reactant side$)$ is favoured?

INSTRUCTIONS: Only answer with $1$ letter A through F on the MS Form.

Answer: A Vessel $1$ contains a partial pressure of $8\mathrm{.}6$atmCO,$6\mathrm{.}2atmC{l}_2$ and $1\mathrm{.}3atmCOC{l}_2$

B Vessel $2$ contains a partial pressure of $2\mathrm{.}6$atmCO,$1\mathrm{.}6atmC{l}_2$ and $93\mathrm{.}6atmCOC{l}_2$

C Vessel $3$ contains a partial pressure of $62\mathrm{.}5$atmCO,$12\mathrm{.}6atmC{l}_2$ and $71\mathrm{.}2atmCOC{l}_2$

D Vessel $4$ contains a partial pressure of $1\mathrm{.}2$atmCO,$2\mathrm{.}9atmC{l}_2$ and $97\mathrm{.}6atmCOC{l}_2$

E Both vessels $1$ and $3$

F Both vessels $2$ and $4$

Question $2$:

Determine $K_p$ for the following chemical equilibrium given the equilibria $1-3$ below:

$2N_{2}O(g)+3O_2(g)2N_2{O}_4(g),K_p=??$

Given:

Equilibrium $1$:

Equilibrium $2$:

Equilibrium $3$:

$2N{O}_2(g)N_2{O}_4(g)$

$2N_2(g)+O_2(g)2N_{2}O(g)$

$N{O}_2(g)\frac{1}{2}{N}_2(g)+O_2(g)$

$K_p=2\mathrm{.}17{10}^2$

$K_p=7\mathrm{.}29{10}^{-36}$

$K_p=2\mathrm{.}44{10}^8$

Assume all equilibria are occurring at the same constant temperature.

INSTRUCTIONS: Give your answer to $3$ significant digits in scientific notation $($example: $1\mathrm{.}23{10}^{-45}$ would be typed in as $1\mathrm{.}23$E$-45)$ in the MS Form