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Question 1 Interpreting Confidence Intervals: If theheights of men and women from the associated data files(MBODY & FBODY-found in the Lab 11 file) are used

Question 1

Interpreting Confidence Intervals:If theheights of men and women from the associated data files(MBODY & FBODY-found in the Lab 11 file) are used to construct a 95% confidence interval for the

difference between the two population means, the result is 11.61 cm

Express the confidenceinterval with the heights of women being population1 and the heights of men being population 2. Choose the correct confidence interval below.

Group of answer choices

17.32

-17.32

-11.61

11.61

Question 2

IQ and Lead Exposure.The data set IQLEAD (found in the lab description) lists full IQ scores for arandom sample of subjects selected from a group with low lead levels in their blood and another random sample of subjects selected from a group withhigh lead levels in their blood. The statistics for these groups are summarized below.

Use a 0.05 significance level to test theclaim that the mean IQ score of people with low lead levels is higher than the mean IQ score of people

with high lead levels.

Low Lead Level: n= 78, x= 92.88462,s= 15.34451

High Lead Level:n= 21,x= 86.90476,s= 8.988352

Are the samples in this case independent meaning we should use a 2-sample Independent T-Test or are they dependent samples meaning we should use a Matched Pairs Design?

Group of answer choices

Independent so 2-Sample Independent Design

Dependent so a Matched Pairs Design

Question 3

IQ and Lead Exposure: Step 1The data set IQLEAD (found in the lab description) lists full IQ scores for arandom sample of subjects selected from a group with low lead levels in their blood and another random sample of subjects selected from a group withhigh lead levels in their blood. The statistics for these groups are summarized below.

Use a 0.05 significance level to test theclaim that the mean IQ score of people with low lead levels is higher than the mean IQ score of people

with high lead levels.

Low Lead Level: n= 78, x= 92.88462,s= 15.34451

High Lead Level:n= 21,x= 86.90476,s= 8.988352

Fill in the blanks to complete Step 1: The hypotheses:

H012= [ Select ] ["57", "-57", "0", "50"]

H112 [ Select ] ["greater than", "less than", "not equal to"] [ Select ] ["57", "-57", "0", "50"]

where1isthe mean from the low lead level group and2is the mean from the high lead level group

Question 4

IQ and Lead Exposure: Step 3 Checking the RequirementsThe data set IQLEAD (found in the lab description) lists full IQ scores for arandom sample of subjects selected from a group with low lead levels in their blood and another random sample of subjects selected from a group withhigh lead levels in their blood. The statistics are for these groups are summarized below.

Use a 0.05 significance level to test theclaim that the mean IQ score of people with low lead levels is higher than the mean IQ score of peoplewith high lead levels.

Low Lead Level: n= 78, x= 92.88462,s= 15.34451

High Lead Level:n= 33,x= 86.90476,s= 8.988352

For each of the requirements necessary for this test, choose the correct answer indetermining if the are met or not.

1.) The population standarddeviations are not equal.

This requirement is met. We can use the sample standard deviations to help gauge if the population standard deviations are equal. True/False [ Select ] ["True", "False"]

2.) The samples are independent. True/False [ Select ] ["True", "False"]

3.) Both samples are random samples True/False [ Select ] ["True", "False"]

4.) The sample sizes are both larger than 30. True/False [ Select ] ["True", "False"]

Question 5

IQ and Lead Exposure: Step 4 CalculationsThe data set IQLEAD (found in the lab description) lists full IQ scores for arandom sample of subjects selected from a group with low lead levels in their blood and another random sample of subjects selected from a group withhigh lead levels in their blood. The statistics are for these groups are summarized below. Use a 0.05 significance level to test theclaim that the mean IQ score of people with low lead levels is higher than the mean IQ score of peoplewith high lead levels.

Low Lead Level: n= 78, x= 92.88462,s= 15.34451

High Lead Level:n= 33,x= 86.90476,s= 8.988352

1: Find the value of the test statistic and p-value following the instructions below:

a) Press STAT & scroll to TESTS & select "2-SampTTest..." (option 4 in TI83Plus) & press Enter (for a hypothesis test of a claim involving two populations

b) Enter the following:

  • Inpt: Stats (The statistics are given above)
  • x1= sample mean from the low lead level group
  • Sx1=sample standard deviation from the low lead level group
  • n1 =sample size from the low lead level group
  • x2= sample mean from the high lead level group
  • Sx2 =sample standard deviation from the high lead level group
  • n2 =sample size from the high lead level group
  • Choose thecorrect direction of the alternative
  • Pooled: Choose NO

c) Highlight "Calculate" and press ENTER & make note of the calculations as you will needthem below.

Enter the value of the T-Test statistic. Round to two decimal places if necessary.

T = _________?

Question 6

IQ and Lead Exposure: Step 4 CalculationsThe data set IQLEAD (found in the lab description) lists full IQ scores for arandom sample of subjects selected from a group with low lead levels in their blood and another random sample of subjects selected from a group withhigh lead levels in their blood. The statistics for these groups are summarized below. Use a 0.05 significance level to test theclaim that the mean IQ score of people with low lead levels is higher than the mean IQ score of peoplewith high lead levels.

Low Lead Level: n= 78, x= 92.88462,s= 15.34451

High Lead Level:n= 33,x= 86.90476,s= 8.988352

1: Find the value of the test statistic and p-value following the instructions below:

a) Press STAT & scroll to TESTS & select "2-SampTTest..." (option 4 in TI83Plus) & press Enter (for a hypothesis test of a claim involving two populations

b) Enter the following:

  • Inpt: Stats (The statistics are given above)
  • x1= sample mean from the low lead level group
  • Sx1=sample standard deviation from the low lead level group
  • n1 =sample size from the low lead level group
  • x2= sample mean from the high lead level group
  • Sx2 =sample standard deviation from the high lead level group
  • n2 =sample size from the high lead level group
  • Choose thecorrect direction of the alternative
  • Pooled: Choose NO

c) Highlight "Calculate" and press ENTER & make note of the calculations as you will needthem below.

Enter the value of the P-Value. Round to three decimal places if necessary.

P-value = __________?

Question 7

IQ and Lead Exposure: Step 4 ConclusionsThe data set IQLEAD (found in the lab description) lists full IQ scores for arandom sample of subjects selected from a group with low lead levels in their blood and another random sample of subjects selected from a group withhigh lead levels in their blood. The statistics for these groups are summarized below. Use a 0.05 significance level to test theclaim that the mean IQ score of people with low lead levels is higher than the mean IQ score of peoplewith high lead levels.

Low Lead Level: n= 78, x= 92.88462,s= 15.34451

High Lead Level:n= 33,x= 86.90476,s= 8.988352

Based on the T-score and the p-value, fill in the blanksbelow to draw the conclusion:

Since the p-value is [ Select ] ["greater than", "less than"] the significancelevel of 0.05, we would [ Select ] ["reject", "fail to reject"] the null hypothesis. This would mean that there [ Select ] ["is", "is not"] asignificant difference in IQ scores between people with low lead levels and high lead levels.

Question 8

IQ and Lead Exposure: Confidence IntervalThe data set IQLEAD (found in the lab description) lists full IQ scores for arandom sample of subjects selected from a group with low lead levels in their blood and another random sample of subjects selected from a group withhigh lead levels in their blood. The statistics for these groups are summarized below. Build a 95% Confidence interval to test theclaim that the mean IQ score of people with low lead levels is higher than the mean IQ score of peoplewith high lead levels.

Low Lead Level: n= 78, x= 92.88462,s= 15.34451

High Lead Level:n= 33,x= 86.90476,s= 8.988352

2: Find the 95% confidence interval

a) Press STAT & scroll to TESTS & select "2-SampTInt..." (option 0 in TI83Plus) & press Enter (for a hypothesis test of a claim involving two populations

b) Enter the following:

  • Inpt: Stats (The statistics are given above)
  • x1= sample mean from the low lead level group
  • Sx1=sample standard deviation from the low lead level group
  • n1 =sample size from the low lead level group
  • x2= sample mean from the high lead level group
  • Sx2 =sample standard deviation from the high lead level group
  • n2 =sample size from the high lead level group
  • Pooled: Choose NO

c) Highlight "Calculate" and press ENTER & make note of the calculations as you will needthem below.

Enter the values of the confidence interval below here. Round each value to two decimal places.

The 95% confidence interval = (_____, _____? )

Question 9

IQ and Lead Exposure: Confidence Interval (cont)The data set IQLEAD (found in the lab description) lists full IQ scores for arandom sample of subjects selected from a group with low lead levels in their blood and another random sample of subjects selected from a group withhigh lead levels in their blood. The statistics for these groups are summarized below. Build a 95% Confidence interval to test theclaim that the mean IQ score of people with low lead levels is higher than the mean IQ score of peoplewith high lead levels.

Fill in the blanksbelowto interpret the confidence interval.

"Based on this sample, we are [ Select ] ["95", "5", "1", "99"] % confident that the true difference in population mean IQ scores betweenthe low lead group and the high lead group is between 1.34 and 10.62posts. Since [ Select ] ["0", "5", "-5"] is [ Select ] ["in", "not in"] in the interval, the sample evidence indicates a difference in IQ scores between the two groups.

Question 10

Do Men and Women Have the SameMean Body TemperatureConsider the sample of bodytemperatures (F) listed in the last column of the file BODYTEMP.

The summarystatistics are given in the table below. Use a 0.01 significance level to test the claim that men and women

have different mean body temperatures. Body temperatures are given in degreesFahrenheit.

Men: n= 15, x= 98.38,s= 0.45

Women: n= 91,x= 98.17,s= 0.65

Upload work demonstrating all 5 completed steps for the hypothesis test. The 5 steps should match the steps in the example posted in the example here: Hypothesis Testing in 5 Steps.pdfDownload Hypothesis Testing in 5 Steps.pdf

Use the first 9 questions of this lab as a guide. Full credit will only be given for a completed test with all 5 steps. For step number 2, write in words: "T-Test statistic for 2 independent samples" or copy the statistics from the Powerpoint.

Female Body Temperatures

AGEPULSESYSDIASHDLLDLWHITEREDPLATEWTHTWAISTARMCBMI
607812260741409.64.7031759.3163.782.327.522.13
248012064561427.14.6422474.5165.588.530.027.20
4968904870727.54.6124877.7163.194.934.429.21
625615080401646.84.0930997.9166.3111.838.735.40
537613258671095.64.3633571.7163.686.532.226.79
1878885296935.44.6427860.9170.978.426.720.85
417810060431226.74.9831260.5153.581.730.525.68
219011472801168.63.7633888.2155.7111.236.936.38
21969454778410.24.3029043.8153.079.223.218.71
19601005441554.14.6623647.9157.063.422.619.43
1998110742311513.05.66310126.6163.7103.840.547.24
5866188076989.24.7146064.8161.390.429.024.91
4410010674391395.94.8131775.6168.693.632.126.60
527613076521228.04.9530481.0156.4111.832.833.11
486412676381007.04.3223972.8159.497.231.928.65
3682905637999.14.3524367.3164.283.930.824.96
486216890571315.73.9335158.0169.080.326.720.31
34721106681594.64.69242107.8161.6120.640.741.28
2278986037906.04.6621754.1161.180.525.220.85
617411270501305.75.2617359.6150.897.129.726.21
219011666731448.94.2322848.9166.679.721.617.62
33901287261846.44.81259115.7175.7119.939.937.48
326811672331128.14.5019375.3169.096.332.026.36
377211266411287.94.36417114.9160.5124.443.244.60
198212660601074.44.6819360.0159.174.529.423.70
51729460622094.94.6424467.3166.783.831.024.22
35781207867775.34.0126677.3151.594.037.233.68
18104943279395.34.1128649.7156.271.224.220.37
60621207664854.74.3720658.4148.790.730.026.41
587214862441629.84.6642682.2168.3103.633.429.02
607212676421115.34.8924479.5159.698.336.431.21
488812672411044.94.3529580.3165.996.633.029.18
317411272441926.34.5628256.4147.679.129.525.89
297212078571105.45.1021164.3165.485.731.023.50
468211076691237.05.30355102.1159.8119.639.539.98
18789866607013.54.8335762.3158.583.230.624.80
5078130724715510.04.6527274.6165.697.531.027.20
2098114546710810.34.29251116.3164.9140.035.542.77
567217486551585.14.4021992.6172.0109.039.031.30
18641085882506.64.2623465.0170.281.827.522.44

Male Body Temperatures

AGEPULSESYSDIASHDLLDLWHITEREDPLATEWTHTWAISTARMCBMI
186013268442138.74.9140964.4178.881.428.420.14
20741206841885.95.5918761.8177.574.826.819.62
438610684711747.34.4425078.5187.884.132.322.26
395410460411216.24.8027386.3172.495.539.029.04
609012280571245.95.1727873.1181.790.129.422.14
18801226250996.45.2427958.5169.069.828.720.48
576612678601143.94.51237134.3186.9137.842.838.45
276811860471226.44.7720079.8183.194.432.023.80
206811040441129.85.0220964.8176.474.229.220.82
1856965633674.05.1020358.1183.469.926.217.27
638011476481083.84.4520676.1169.695.232.026.46
20621287846945.65.41174118.4185.4117.539.934.45
24741087662696.65.4521956.2166.177.026.220.37
46601267845774.94.2730273.4169.390.533.125.61
295211682431209.64.90285126.9193.5122.037.933.89
63601387639848.64.6025484.4173.1104.032.228.17
21661105041865.24.9319597.8171.6104.137.933.21
45641448447779.24.2829066.5180.876.429.920.34
406411270462016.64.7424090.5175.398.637.029.45
504613074561963.24.9827083.7178.389.736.026.33
486813682381796.95.2026488.7172.8102.133.729.71
645814670371407.15.1720880.4165.2104.632.629.46
186810662611176.94.8527164.0176.677.626.120.52
507013676411177.05.7738665.7174.287.530.221.65
20561228656878.45.0920358.9181.769.125.117.84
20661128059785.95.2422382.4176.083.436.026.60
477812890401595.15.1826185.1173.796.133.228.21
1968114565411310.05.3428287.7177.197.235.327.96
556210068401554.44.89184111.9174.5122.436.536.75
23701067875857.15.5920470.9180.481.531.021.79
21721347855907.95.94287101.8177.397.538.832.38
197412868481048.15.3921999.0172.5106.736.433.27
646410880501545.65.24257100.5180.2109.636.930.95
305010668571144.14.7220678.9172.791.833.226.45
437011268381569.55.3434279.2168.696.734.027.86
235812068781034.95.2331986.1178.386.638.227.08
646014062451458.94.98251100.8176.7118.136.032.28
408898568213511.05.0617876.4174.881.534.725.00
238412668441238.65.6422077.4172.192.131.926.13
447615486511706.95.4726889.7173.4103.337.529.83

IQLEAD

LEADAGESEXYEAR1YEAR2IQVIQPIQF
11112518618570
1913128829085
111130297010786
1612930728576
11112347210084
1612925959796
16125248910194
11522415576456
1722416116111115
17131249510097
11322119827677
11022927116136128
112132299910099
11213632749080
11513025100135118
110129237210486
11512828126149141
1922819809988
18134228610796
11112122949996
1713527100113107
111239387210486
16136316310180
1611925101111107
191292485118101
1132124859991
1922220124122125
16123181058796
113121188111899
16132268711399
11222627100128115
182202491121106
19122299111105
17236318910496
11212434575150
16238379910099
19214255811385
11421820978288
1151241694146120
114120218210793
1923334928387
17236278910898
11221822699378
181312687114100
171333097113105
11522733829487
16228268510694
11422423899289
1713023857980
1131242392129111
1121292495114104
1613831769985
17131398011094
1912832669075
11222223678573
11512216639476
1101272887127107
19124337910188
11323634829989
112210388211396
1623021708072
111227318111597
11523433728576
1413534101112107
142272795112104
1312326819285
1412720619776
141227949795
1313228859186
14133317610589
1413228728476
1423537979596
151353495108101
142303497118108
142342387118102
1521825748677
1413825668974
16236238610092
21414238727872
2724034859790
27140348010792
21324133678071
2614132859086
21514130798379
212143327010183
2916625105121114
292513992108100
28144318910093
214264387411091
29143328611198
21124324879791
2714037515146
2924035809485
2414722878082
23244349410197
2524529919291
24141349210092
2525130817777
2314232111108111
2315036758578
31016853759382
310253498710093
3914840769785
3614140767975
3514547769785
31226245927180
361494391111101
3725258829989
31226148808580
3814150919994
3615940819788
361575897111104
38158577610488
31124051859388
3915748809083
3814843100107104
34157438610896
3415149797876
3415947709580
3314445847879
3324245698675

Body Temp

98.6
98.6
98.0
98.0
99.0
98.4
98.4
98.4
98.4
98.6
98.6
98.8
98.6
97.0
97.0
98.8
97.6
97.7
98.8
98.0
98.0
98.3
98.5
97.3
98.7
97.4
98.9
98.6
99.5
97.5
97.3
97.6
98.2
99.6
98.7
99.4
98.2
98.0
98.6
98.6
97.2
98.4
98.6
98.2
98.0
97.8
98.0
98.4
98.6
98.6
97.8
99.0
96.5
97.6
98.0
96.9
97.6
97.1
97.9
98.4
97.3
98.0
97.5
97.6
98.2
98.5
98.8
98.7
97.8
98.0
97.1
97.4
99.4
98.4
98.6
98.4
98.5
98.6
98.3
98.7
98.8
99.1
98.6
97.9
98.8
98.0
98.7
98.5
98.9
98.4
98.6
97.1
97.9
98.8
98.7
97.6
98.2
99.2
97.8
98.0
98.4
97.8
98.4
97.4
98.0
97.0

Hypothesis Testing Steps

image text in transcribedimage text in transcribedimage text in transcribed
C My Overvie X UB Quiz: Lab A X Hypothesis X UB Topic: New X K! Kahoot! X A Homework X *Course Her X My Progres X + X C O File | C:/Users/joanna/Downloads/Hypothesis%20Testing%20for%20Proportions%20in%205%20Steps.pdf E Hypothesis Testing for Proportions in 5 Steps.pdf 1 / 3 50% + Hypothesis Testing in 5 Steps For all questions throughout the semester that ask you to complete a hypothesis test, please use this outline. It is adaptable to difference situations that ask you to complete a hypothesis test. Step #1: State the hypotheses Sometimes it is helpful to write out the hypothesis in words first then in symbolic form. Always include the symbolic form Be sure you have the correct symbols. Is the test about the population mean? Population standard deviation? Population proportion? Choosing the correct symbol is important. (Notice the word population in all of these: Hypothesis testing is based on population values. Never use sample statistic symbols here, only population symbols . For the null hypothesis, there is only one option: (based on equality Ho: 6= For the alternative hypothesis, there are three options based on the problem H1:6> H1:8 0.50 (alternative is directional. Notice the symbol for the population mean) In words: (This is optional but can be helpful) H.: The population proportion of babies that are boys is 50%% H1: The population proportion of babies that are boys is greater than 50% 2.) Choose a test statistic in this example, we are dealing with a single sample and testing the sample proportion. We can use a Z-Statistic. As the value for alpha is stated in the problem, we use a = 0.01 with a = 0.01 P(1 - P) 3.) State the assumptions First, we need to assume the sample is a random sample so that it represents the population well. In this problem, this information is not stated so we need to state it here. We are assuming the sample is a simple random sample as it is not stated in the problem. . Second, we need to check to see if the requirements for a binomial distribution are met. In this example, there are 291 independent trials with only 2 possible outcomes. The probability remains constant from trial to trail. Therefoe, the requirements for a binomial distribution are met . Third, we need to test the sample size. In this case, testing that np 2 5 and nq 2 5 291(0.82) = 293 2 5 2 291(0.18) = 52 2 5 Therefore, this requirement is met. 4.) Calculations a.) 1st, the test statistic: (This is always based on the statistic chosen in step 2) 2 - 0.82 - 0.50 = 10.96 0.50 - 0.50 291 b.) 2nd, we can calculate the p-value. (Here, you have the option of either the p-value or a critical value. In this case, I used the p-value. Keep in mind, your conclusion will be the same either way.) Hypothesis Testing.pdf Hypothesis Testing..pdf ~ D Cliff Edge Image Ph.gif Show all X Type here to search 14% 5:57 PM 10/31/2022C My Overvie X UB Quiz: Lab A X Hypothesis X UB Topic: New X K! Kahoot! X A Homework X *Course Her X My Progres X + X C O File | C:/Users/joanna/Downloads/Hypothesis%20Testing%20for%20Proportions%20in%205%20Steps.pdf E Hypothesis Testing for Proportions in 5 Steps.pdf 2 / 3 50% + With a = 0.01 P(1 - P) 3.) State the assumptions First, we need to assume the sample is a random sample so that it represents the population well. In this problem, this information is not stated so we need to state it here. We are assuming the sample is a simple random sample as it is not stated in the problem. . Second, we need to check to see if the requirements for a binomial distribution are met. In this example, there are 291 independent trials with only 2 possible outcomes. The probability remains constant from trial to trail. Therefoe, the requirements for a binomial distribution are met Third, we need to test the sample size. In this case, testing that np 2 5 and nq 2 5 291(0.82) = 293 2 5 291(0.18) = 52 2 5 Therefore, this requirement is met. 4.) Calculations: a.) 1st, the test statistic: (This is always based on the statistic chosen in step 2) 2 0.82 - 0.50 10.96 9.50 . 0.50 291 b.) 2nd, we can calculate the p-value. (Here, you have the option of either the p-value or a critical value. In this case, I used the p-value. Keep in mind, your conclusion will be the same either way. P - value = P(Z > 10.96)

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