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Question 1: Part 2 of 4 Compute the P-value. Round the answer to at least four decimal places. P-value = Part: 2 / 4 Part

Question 1:

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Part 2 of 4 Compute the P-value. Round the answer to at least four decimal places. P-value = Part: 2 / 4 Part 3 of 4 Determine whether to reject Ho. (Choose one) V the null hypothesis Ho. Part: 3 / 4 Part 4 of 4 State a conclusion. There is enough evidence to conclude that the mean weight of one-year-old boys is less than 25 pounds.According to past studies, 33% of gamers experience motion sickness from using virtual reality (VR) glasses. Because of changes to the way VR glasses are manufactured, a consumer advocate claims the proportion, p, of gamers who will experience motion sickness from using modern VR glasses is more than 33%. He tests his claim by choosing 180 gamers at random and having each of them use a pair of newly-manufactured VR glasses. Of these gamers, 68 say that using the glasses makes them motion sick. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to conclude that the proportion, p, of all gamers who will experience motion sickness from using modern VR glasses is greater than 33%. (a) State the null hypothesis Ho and the alternative hypothesis H, that you would use for the test. Ho : 0 p H: I 020 0=0 0*0 X (b) For your hypothesis test, you will use a Z-test. Find the values of np and n (1 -p) to confirm that a Z-test can be used. (One standard is that np2 10 and n (1 -p) 2 10 under the assumption that the null hypothesis is true.) Here n is the sample size and p is the population proportion you are testing. np= 0 X 5 n (1-p)=0(c) Perform a Z-test and find the p-value. Here is some information to help you with your Ztest. A P 'P p (1 10) n o The p-value is the area under the curve to the right of the value of the test statistic. o The value of the test statistic is given by Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed Step 2: Enter the test statistic. (Round to 3 decimal places.) :l Step 3: Shade the area represented by the p-value. 9 Step 4: Enter the p-value. (Round to 3 decimal places.) :l (d) Based on your answer to part (c), choose what can be concluded, at the 0.05 level of significance, about the proportion of all gamers who will experience motion sickness from using modern VR glasses. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. 50, there is enough evidence to conclude that more than 33% of all gamers will experience motion sickness from using modern VR glasses. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. 50, there is not enough evidence to conclude that more than 33% of all gamers will experience motion sickness from using modern VR glasses. Since the p-value is greater than the level of significance, the null hypothesis is rejected. 50, there is enough evidence to conclude that more than 33% of all gamers will experience motion sickness from using modern VR glasses. Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to conclude that more than 33% of all gamers will experience motion sickness from using modern VR glasses. Netflix: A study conducted by a technology company showed that the mean time spent per day browsing the video streaming service Netflix for something to watch was 20 minutes. Assume the standard deviation is o = 5. Suppose a simple random sample of 109 visits taken this year has a sample mean of x =21 minutes. A social scientist is interested to know whether the mean time browsing Netflix has changed. Use the a = 0.10 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 5 Part 1 of 5 (a) State the appropriate null and alternate hypotheses. Ho: 00 0=0 HE This hypothesis test is a (Choose one) test. XHouse prices: Data from the Denver Metro Association of Realtors indicates that the mean price of a home in Denver, Colorado, in 2018 was 260.7 thousand dollars. A random sample of 58 homes sold in 2019 had a mean price of 288 thousand dollars. Can you conclude that the mean price in 2019 differs from the mean price in 2018? Assume the population standard deviation is (S: 125. Use the a: 0.05 level of significance and the P-value method with the TI-84 Plus calculator. Partlof7 a (a) State the appropriate null and alternate hypotheses. H01|p= 260.7l H1: | u260.7| This hypothesis test is a two-tailed V test. Part:1/7 - Part20f7 (b) Compute the value of the test statistic. Round the answer to two decimal places. z=l 1.663 x 63 A 95% confidence interval for u is computed to be (2.50, 2.70). For each of the following hypotheses, state whether Ho will be rejected at 0.05 level. Part 1 of 4 Ho: M= 2 versus H1 : M#2 Since the 95% confidence interval does not contain |Ho, then Ho will be rejected at the 0.05 level. Part 2 of 4 X Ho : M= 3 versus H1 : 1#3 Since the 95% confidence interval contains Mo, then Ho will not be rejected at the 0.05 level. Correct Answer: Since the 95% confidence interval does not contain Mo, then Ho will be rejected at 0.05 level. Part 3 of 4 X Ho: M= 4.8 versus H1 : 1 #4.8 Since the 95% confidence interval contains Mo, then Ho will be rejected at the 0.05 level.Part4 0f4 H0: ii: 1.4 versus H1: \"#14 Since the 95% confidence interval 110, then H0 be rejected at X 6) the 0.05 level. does not contain Big babies: The National Health Statistics Reports described a study in which a sample of 330 one-year-old baby boys were weighed. Their mean weight was 25.4 pounds with standard deviation 5.3 pounds. A pediatrician claims that the mean weight of one-year-old boys is greater than 25 pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the a = 0.05 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 5 Part 1 of 5 (a) State the appropriate null and alternate hypotheses. Ho H = 25 00 0=0 H: M > 25 This hypothesis test is a two-tailed test. X 5 left-tailed right-tailed two-tailed

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