Question 1 The 2009 holiday retail ston, which kicked off on November 27, 2009 (the day after Thank giving), had been marked by somewhat lower self-reported consumer spending than Wilson during the comparable period in 2008. To get an estimate of consumer spending, 436 randomly sampled American adults were surveyed. Daily consumer spending for the six-day period after Thanksgiving, spanning the Black Friday weekend and cyber Monday, averaged $84.71. A 95% condidence interval based on this sample is (880-31, 889.11). Determine whether the following statements are true or false, and explain your reasoning 60 50 100 150 200 256 200 Spending (a) (1 point) We are 95% confident that the average spending of these 436 American adults is between $80.31 and $89.11. (b) (1 point) This contidence interval is not valid since the distribution of spending in the mmple is right slowed. (c) (1 point) 95% of random samples have a sample mean between $80.31 and $99.11. (d) (1 point) We are 95% confident that the average spending of all American adults is be tween $80.31 and $89.11. (1 point) A 90% confidence interval would be murrower than the 95% confidence interval since we don't need to be sure about our estimate (1 point) In order to decrease the margin of error of a 95% confidence interval to a third of what it is now, we would need to use a sumple 3 times larger (g) (1 point) The margin of error is 4.4 in 1 Question 2 Continue the previous question, (a) (1 point) A local news anchor claims that the average spending during this period in 2009 was $100, What do you think of her claim? (b) (1 point) Would the news anchor's claim be considered reasonable based on a 90% confi- dence interval? Why or why not? (Do not actually calculate the interval)