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QUESTION 1 The electron configuration for P (Z.=15) is: O 152 282 2p8 382 3p7 O 182 282 2p62d5 O 182 282 2p4 352 3p5
QUESTION 1 The electron configuration for P (Z.=15) is: O 152 282 2p8 382 3p7 O 182 282 2p62d5 O 182 282 2p4 352 3p5 O 182 282 2p 3s 3p3 QUESTION 2 According to Pauli's exclusion principle, an atomic orbital can hold a maxim of: O Three electrons with parallel spins O Two electrons with opposite spins O One electron only. O Two electrons with parallel spins QUESTION 3 The electron configuration (182 2s22p?) represents: O Aluminum O Beryllium O Carbon O Boron
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