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QUESTION 1 The process for producing cassava flour ( shown in the figure below ) involves mixing wet, mashed cassava with dried cassava flakes in

QUESTION 1
The process for producing cassava flour (shown in the figure below) involves mixing wet,
mashed cassava with dried cassava flakes in a 90:10 weight ratio and passing the mixture
through a granulator before drying using a spray dryer. The wet, mashed cassava contains
82% water wet basis and the dried cassava flakes contain 3% water wet basis. There are no
losses from the material entering and leaving the granulator. The moisture content of the
final product (cassava flour) is negligible.
Calculate the following:
1.1 The amount of dried cassava flakes (X kg) entering the mixer and the amount of water
(Z kg) that must be removed by the spray dryer for every 100 kg of cassava flour
produced. (8)
1.2 The moisture content (in % m/m wet basis) to the nearest whole number of the
granulated paste fed to the spray dryer. (4)
[12 MARKS]
QUESTION 2
A cold store is to be erected to maintain an internal temperature of 18oC with a surrounding
air temperature of 25oC. It is to be constructed of concrete blocks 20 cm thick and then 15 cm
of polystyrene foam. The surface coefficients of heat transfer are 10 J/m2soC for the external
air and 6 J/m2soC for the internal air and the store is 40 x 20 x 7 m high. Thermal conductivity
of concrete is 0.87 J/msoC and for polystyrene foam 0.036 J/msoC. Ignoring the heat loss
through the floor, determine the rate of heat transfer in kW (to the nearest whole number)
into the cold store from its surrounding air.
q = U A T
1/U =1/hi + z1/k1+ z2/k2+1/ho
[10 MARKS]
MIXER GRANULATOR SPRAY DRYER
Wet, mashed cassava (Y kg)=9Xkg
82% water
Dried cassava flakes (X kg)
3% water
Water (Z kg)
Cassava flour (100 kg)
0% water
Granulated
paste
Page 3 of 5
QUESTION 3
Apple juice at 25oC with 10% total solids is being concentrated to 50% total solids in a single-
effect evaporator. The product moisture evaporates at 65oC, while saturated steam is being
supplied at 100oC. Condensate is released at 100oC. The feed material enters the evaporator
at a rate of 200 kg/h. A small amount of energy, 2500 kJ/h, leaves the evaporator as losses to
the surrounding environment. The overall heat transfer coefficient is 943 W/m2oC. The
specific heat of the feed is 4 kJ/kgoC and of concentrated product is 3.2 kJ/kgoC. Calculate:
3.1 The steam economy (mv/ms) for the evaporator. (12)
3.2 The area of heat transfer for the evaporator in m2 to two decimal places. (5)
{Rate of heat transfer q = UA(Ts T1)= ms(Hvs Hcs)}
[17 MARKS]
QUESTION 4
1000 kg/min of air, originally at 62oC dry bulb temperature and 35oC wet bulb temperature is
heated to 98oC dry bulb temperature and then used in drying by passing consecutively over 2
shelves containing diced apples in a tray dryer. The following conditions are applicable to the
dryer:
After the first drying cycle in the first shelf, the air regains its original dry bulb
temperature (62oC).
After the first drying cycle, the air is reheated to 98oC dry bulb temperature and used
for the second drying cycle in the second shelf.
After the second drying cycle in the second shelf, the air regains its original dry bulb
temperature (62oC).
After the second drying cycle, the air is mixed with another stream of air (named X) to
produce a resultant air stream which has a dry bulb temperature of 72oC and moisture
content of 64 g/kg dry air. The weight of air stream X is half that of the air obtained
after the second drying cycle.
4.1 On a copy of the psychrometric chart, show and clearly label the following:
The two air heating processes (2)
The two drying cycles (2)
The position of air stream X (4)
4.2 Determine the total rate of removal of water in kg/s (to 2 decimal places) from the
diced apples in the tray dryer. (7)
4.3 Estimate the moisture content and the specific volume of air stream X.(4)
[19 MARKS]

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