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Question 1. Version 1*/1. Score: 0/1 Which of the following is not a conclusion of the Central Limit Theorem? The distribution of the sample data

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Question 1. Version 1*/1. Score: 0/1 Which of the following is not a conclusion of the Central Limit Theorem? The distribution of the sample data will approach a normal distribution as the sample size increases. The mean of all sample means is the the population mean. The standard deviation of the sample means is the population standard deviation divided by the square root of the sample size. The distribution of the sample means will approach as normal distribution as the sample size increases. Score: N/A/1 Message instructor Question 2. Version 1*/1. Score: 0/1 When using the central limit theorem for means with n = 90, it is not necessary to assume the distribution of the population data is normally distributed. O True O False Score: N/A/1 Message instructor Question 3. Version 1*/1. Score: 0/1 If x represents a random variable with mean 126 and standard deviation 14, then the standard deviation of the sampling distribution of the means with sample size 49 is 2. O True O FalseQuestion 4. Version 1*/1. Score: 0/1 If the sample size is 36 and the population standard deviation is 24, then the standard deviation of the sampling distribution for the mean is 4. O True O False Score: N/A/1 Message instructor Question 5. Version 1*/1. Score: 0/1 The population mean will always be the same as the mean of all possible X that can be computed from samples of size 45. O True O False Score: N/A/1 Message instructor Question 6. Version 1*/1. Score: 0/1 The symbol ur represents the mean of a sample of size n. O False O True Score: N/A/1 Had help available: Written Example 7 Message instructorQuestion 7. Version 1*/1. Score: 0/1 The symbol oz represents the population standard deviation of all possible sample means from samples of size n. True O False Score: N/A/1 Had help available: Written Example Message instructor Question 8. Version 1*/1. Score: 0/1 The symbol & represents the population mean of all possible sample means of size n. O False O True Score: N/A/1 Had help available: Written Example Message instructorQuestion 9. Version 1*/1. Score: 0/4 The lengths of pregnancies are normally distributed with a mean of 262 days and a standard deviation of 16 days. For each answer below, report to 1 decimal place. The first box MUST be the smaller number in each question. A. In what range of days would you expect to find the middle 98% of all pregnancies? Between and B. If you were to draw samples of size 16 from the population, in what range of days would you expect to find the middle 98% of most averages for the lengths of the pregnancies? Between and Score: N/A/1 N/A/1 N/A/1 N/A/1 Message instructor Question 10. Version 1*/1. Score: 0/7 The average number of miles (in thousands) that a car's tire will function before needing replacement is 65 and the standard deviation is 10. Suppose that 13 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. a. What is the distribution of X? X ~ N( b. What is the distribution of ? a - NO c. If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 66.1 and 69.7. d. For the 13 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 66.1 and 69.7. e. For part d), is the assumption that the distribution is normal necessary? O NoO YesQuestion 11. Version 1*/1. Score: 0/7 The average amount of money spent for lunch per person in the college cafeteria is $7.07 and the standard deviation is $2.59. Suppose that 8 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible. a. What is the distribution of X? X - N( b. What is the distribution of ? a - NO c. For a single randomly selected lunch patron, find the probability that this patron's lunch cost is between $7.32 and $8.08. d. For the group of 8 patrons, find the probability that the average lunch cost is between $7.32 and $8.08. e. For part d), is the assumption that the distribution is normal necessary? O NoO Yes Score: N/A/1 N/A/1 N/A/1 N/A/1 N/A/1 N/A/1 N/A/1 Had help available: Written Example Message instructor Question 12. Version 1*/1. Score: 0/7 The amount of coffee that people drink per day is normally distributed with a mean of 17 ounces and a standard deviation of 6 ounces. 35 randomly selected people are surveyed. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N( b. What is the distribution of ? & ~ NO c. What is the probability that one randomly selected person drinks between 16.7 and 17.3 ounces of coffee per day? d. For the 35 people, find the probability that the average coffee consumption is between 16.7 and 17.3 ounces of coffee per day. e. For part d), is the assumption that the distribution is normal necessary? O Yes No Score: N/A/1 N/A/1 N/A/1 N/A/1 N/A/1 N/A/1 N/A/1 Had help available: Written Example Message instructorQuestion 13. Version 1*/1. Score: 0/7 The average production cost for major movies is 67 million dollars and the standard deviation is 21 million dollars. Assume the production cost distribution is normal. Suppose that 36 randomly selected major movies are researched. Answer the following questions. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N( b. What is the distribution of ? X - N( c. For a single randomly selected movie, find the probability that this movie's production cost is between 65 and 70 million dollars. d. For the group of 36 movies, find the probability that the average production cost is between 65 and 70 million dollars. e. For part d), is the assumption of normal necessary? O YesO No Score: N/A/1 N/A/1 N/A/1 N/A/1 N/A/1 N/A/1 N/A/1 Had help available: Written Example Message instructor

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