QUESTION 10 Questions 10 - 14 concern the following idea: A tea merchant has customers who want more tannin in their tea for a more bitter flavour. She developed a new blend of tea leaves which she believes will increase the amount of tannin that is released into a cup of tea brewed for 3 minutes. With the previous blend there was an average of 103mg of tannin in a cup of tea. She randomly selected 60 samples of the new blend of tea and brewed them for 3 minutes each, and measured the tannin levels in each cup of tea. These samples gave a mean of X = 104.9mg and a standard deviation of S = 6.2mg If you were trying to show support for the claim that the new blend of tea has more tannin than the old, select the necessary null and alternative hypotheses for conducting a hypothesis test (let , be the population mean amount of tannin in a cup of tea with the new blend). O a. Ho X = 104.9 Hi x = 104.9 Ob. How=103 Hip = 103 Oc. H : #= 104.9 H : H > 104.9 O d. H: M= 103 H : H > 103QUESTION 9 Questions 1-9 concern the following idea: A WA hotel chain is investigating how customers in different regions of WA spend money while staying at the hotel. The current analysis concerns how much money people are spending in the hotel restaurant per day, broken up by region (Perth, Albany, or Broome). They want to know in which region(s) customers are spending the least, so that they can promote the hotel restaurant more in those regions. Let up, JA and pB be the population mean restaurant spending per day for Perth, Albany, and Broome respectively, and oz, of and oz be their respective population variances. An ANOVA was performed on the data and some of the output is given below, with some entries obscured with ?? mean sd n Perth 33.58 14.10 29 Albany 24.36 10.76 17 Broome 23.24 11.34 21 summary (AnovaModel) Of Sum Sq Mean Sq F value Pr( >F) region ?? 1606 ?? ?? 0.00849 Residuals ?? 9990 156.1 Fit: aov(formula = spend ~ region, data = tourism) Linear Hypotheses Estimate Std. Error t value Pr(>It)) Albany - Perth == 0 -9.223 3.816 -2.417 0.0478 Broome - Perth == 0 -10.345 3.580 2.890 0.0144 Broome - Albany == 0 -1.122 4.076 -0.275 0.9590 Levene's Test for Homogeneity of Variance (center = "median") Of F value Pr(>F) group 2 0.6513 0.5248 64 Assume that the unadjusted 95% confidence interval for the mean daily spending in the hotel restaurant in Perth has been calculated as ($28.95, $38.22). An analyst is wondering if there was significant evidence that the mean daily spending in the hotel restaurant in Perth is different to $30. Just using the confidence interval, what would be the correct conclusion be (use a = 0.05)? O a. Since $30 is within the confidence interval, there is no significant evidence that up is different to $30. O b. The majority of the confidence interval is greater than $30, so there is significant evidence that pp > $30. O c. Since $30 is within the confidence interval, there is significant evidence that up is different to $30. O d. We have only been provided with a confidence interval, so can't make this type of conclusion