Question 10 We want to use the comparison test to determine whether ( + 2x ) 1/7 is convergent. Choose the correct argument. The integral is divergent since 1 1 (x + 2x)1/7 2 1 (1/7) x for all a _ 1 and (1/7) x di = 0 O The integral is convergent since 1 1 (x + 2x) 1/7 S 1 21/7 for all x 2 1 and de =- 71/7 1/7- 1 0 ). Answer: Number FORMATTING: If you round your answer, ensure that the round-off error is less than 0.1% of the value.b) Knowing that 1 7/2 and 8 N | DO dx = 0o 2+ 2x2 6 + 2 cos I 6 The integral is divergent since 6 > and de = co. 2+ 2x2 8 8 The integral is convergent since 6 + 2 cos I for all a _ 1 and de = 25x3 for all x 2 1, hence O 1 1 . 00 25x3 + 16x1/4 523/2 and I s J1 23/2 = 2/5. The integral is divergent since 25x3 + 16x1/4 > 1, hence O 1 1 .0O dx V25x3 + 16x1/4 VAI23/2 and 1 2 - V41 1 2-3/2 = 00 O 1 The integral is convergent since 25x3 + 16x1/4 > 16x /4 for all > > 1, hence 1 V25x3 + 1621/4 4x1/8 and I = 4 /1 dx 1/8 = -2/7. The integral is divergent since 25x3 + 16x1/4 1, hence O 1 1 dx V25x3 + 16x1/4 V41 1/8 and 1 2 41 J1 = 00 21/8