QUESTION 10 Zinc plays an important role in many biochemical reactions in the body. The concentration of zinc can be determined in foods digested with acid, using Inductively coupled plasma spectroscopy (ICP), attet calibrating the instrument using Zn2+ standards. For this purpose, a stock solution was prepared by dissolving 0.521 g of zinc chloride in water and diluting the solution to 250 mL in a volumetric flask The amount of stock solution needed to prepare 20.0 mL of the following ppm wiv Zn2+ calibration standards is: CI 35 45 g/mol Zn 65 39 g/mol Note More than one answer may be correct Negative marking will apply to incorrect answers, so do not guess the answer CA The amount of stock solution needed to prepare 200 ml. of a 1 pom Zn2+ solution is 0.010 m. B. The amount of stock solution needed to prepare 200 ml. of a 5 ppm Zn2solution is 0.10 mL OC The mount of stock wolution needed to prepare 20.0 mL of a 500 ppm Zn2+ solution is 100 ml OD The amount of stock solution needed to prepare 200 ml of a 25 ppm Zn2+ solution is 0 500 ml DE The amount of stock solution needed to prepare 200 mL of a 10 ppm Zn2+ solution is o 20 ml. 10