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Question 12 Not yet answered Marked out of 3 The output of this algorithms is txt[] = ABAAABAADAABAAABAA pat[] = AABA M = strlen(pat) N
Question 12 Not yet answered Marked out of 3 The output of this algorithms is txt[] = "ABAAABAADAABAAABAA" pat[] = "AABA" M = strlen(pat) N = strlen(txt) for i = 0 to i=N-M for j = 0 toj = M-1 if (txt[i + j] != pat[i]) break if (j = M) output i 13 @ 39 9 3.9 13
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