Question 18 3 pts Sliding block 5 Frictionlcss surface Part 2 of 2. For the following system above, with large block 5 with mass M on the frictionless surface and small block H with mass m suspended by a cable. For the mass M, let the direction right be +x, and the mass m, the direction down is -y. From part 1, the magnitude of ax for block 5 is the same as the magnitude a, for block H. Substitute a for ax and -a for a,. Set the values of Tin each equation to each other and solve for the value of a, the acceleration, symbolically. For example, it might look like this: T = Ma and T -mg = -ma. You need to show this from the FBD of each object. Hint: Block S has only one force acting on it in +x, block H has two forces acting on it in -y. Also, block 5 has a normal force FN, but that is in +y, and it is not needed. a = -g[(m)/(M+ml1 a a = g [(m)/(M+m)] a = g (m+M)/(m) a = (m+M)/(mg) a = 2g [(m)/(M+m)]