Question 18(1 point)

You move out into the country and you notice every Spring there are more and more Deer Fawns that appear. You decide to try and predict how many Fawns there will be for the up coming Spring.

You collect data to, to help estimate Fawn Count for the upcoming Spring season. You collect data on over the past 10 years.

x1 = Adult Deer Count

x2 = Annual Rain in Inches

x3 = Winter Severity

• Where Winter Severity Index:
• 1 = Warm
• 2 = Mild
• 3 = Cold
• 4 = Freeze
• 5 = Severe

Is there a significant linear relationship between these 3 variables and Fawn Count?

If so, what is/are the significant predictor(s) for determining Fawn Count?

See Attached Excel for Data.

Deer data

Question 18 options:

Yes,

Adult Count, p-value = 0.01188964 < .05, Yes, Adult Count is a significant predictor for Fawn Count.

Annual Rain in Inches, p-value = 0.004661804 < .05, Yes, Annual Rain in Inches is a significant predictor for Fawn Count.

Winter Severity, p-value = 0.00462881 < .05, Yes, Winter Severity is a significant predictor for Fawn Count.

No,

Adult Count, p-value = 0.01188964 < .05, No, Adult Count is not a significant predictor for Fawn Count.

Annual Rain in Inches, p-value = 0.004661804 < .05, No, Annual Rain in Inches is not a significant predictor for Fawn Count.

Winter Severity, p-value = 0.00462881 < .05, No, Winter Severity is not a significant predictor for Fawn Count.

Yes,

Adult Count, p-value = 0.01188964 > .05, Yes, Adult Count is a significant predictor for Fawn Count.

Annual Rain in Inches, p-value = 0.004661804 > .05, Yes, Annual Rain in Inches is a significant predictor for Fawn Count.

Winter Severity, p-value = 0.00462881 > .05, Yes, Winter Severity is a significant predictor for Fawn Count.

No,

Adult Count, p-value = 0.01188964 > .05, No, Adult Count is not a significant predictor for Fawn Count.

Annual Rain in Inches, p-value = 0.004661804 > .05, No, Annual Rain in Inches is not a significant predictor for Fawn Count.

Winter Severity, p-value = 0.00462881 > .05, No, Winter Severity is not a significant predictor for Fawn Count.

Question 19(1 point)

With Obesity on the rise, a Doctor wants to see if there is a linear relationship between the Age and Weight and estimating a person's Systolic Blood Pressure. Using that data, find the estimated regression equation which can be used to estimate Systolic BP when using Age and Weight as the predictor variable.

See Attached Excel for Data.

BP data

Question 19 options:

Systolic BP = 31.73252234 + 0.938835263(Age) + 0.309246373(Weight)

Systolic BP = 11.05638371+ 0.230153049(Age) + 0.120862651(Weight)

Systolic BP = 31.73252234 + 0.984797135(Age) + 0.969825398(Weight)

Systolic BP = 31.73252234 + 0.965183151(Age) + 2.666383416(Weight)

Question 20(1 point)

You are thinking about opening up a Starbucks in your area but what to know if it is a good investment. How much money do Starbucks actually make in a year? You collect data to, to help estimate Annual Net Sales, in thousands, of dollars to know how much money you will be making.

You collect data on 27 stores to help make your decision.

x1 = Rent in Thousand per month

x2 = Amount spent on Inventory in Thousand per month

x3 = Amount spent on Advertising in Thousand per month

x4 = Sales in Thousand per month

x5= How many Competitors stores are in the Area

Is there a significant linear relationship between these 5 variables and the Annual Net Sales of a Starbucks?

If so, what is/are the significant predictor(s) for determining the Annual Net Sales of a Starbucks?

See Attached Excel for Data.

Starbuck Sales data

Question 20 options:

Yes,

Inventory, p-value = 0.068486021 > .05, No, Inventory is not a significant predictor for Annual Net Sales

# Competitor Store, p-value = 0.258240292 > .05, No, # Competitor Stores, is not a significant predictor for Annual Net Sales.

Yes,

Rent, p-value = 0.012388536 < .05, Yes, Rent is a significant predictor for Annual Net Sales

Advertising, p-value = 0.003599968 < .05, Yes, Advertising is a significant predictor for Annual Net Sales

Sales per Month,p-value = 0.0000876481 < .05, Yes, Sales per Month, is a significant predictor for Annual Net Sales

No,

Rent, p-value = 0.012388536 < .05, Yes, Rent is a significant predictor for Annual Net Sales

Advertising, p-value = 0.003599968 < .05, Yes, Advertising is a significant predictor for Annual Net Sales

Sales per Month,p-value = 0.000876481 < .05, Yes, Sales per Month, is a significant predictor for Annual Net Sales

No,

Inventory, p-value = 0.068486021 > .05, No, Inventory is not a significant predictor for Annual Net Sales

# Competitor Store, p-value = 0.258240292 > .05, No, # Competitor Stores, is not a significant predictor for Annual Net Sales.