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Question 2 4 points Save Answer For the last 10 years, an engineer has saved $800 every 6 months for the repairs agreement. What is

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Question 2 4 points Save Answer "For the last 10 years, an engineer has saved $800 every 6 months for the repairs agreement. What is the equal amount after the last payment, if the interest rate 8% per year compounded quarterly?" 37265 8559 15327 24589 54613 78355 110848 None of them Question 1 4 points Save Answer "The Engineering company expects the cost of maintenance for a piece of equipment to be $10000 in year 1, to be $10900 in year 2, and to increase annually by $900 through year 8. At an interest rate of 8% per year, determine the present worth of 8 years of maintenance costs." 62808 66369 73491 69930 77053 80614 None of them

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