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Question 2(Multiple Choice Worth 1 points) (09.03 MC) A particle moves according to the position vector s(() = (sint,cos 21). Determine when the particle is

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Question 2(Multiple Choice Worth 1 points) (09.03 MC) A particle moves according to the position vector s(() = (sint,cos 21). Determine when the particle is at rest. Of =0 ot-5 Of = n Or = 2n Question 3(Multiple Choice Worth 1 points) (09.03 MC) At t = 0 a particle is at point (1, -2). Find the position of the particle that moves with velocity vector v(t) = (t- co O 510 2 10 9 M CQuestion 1(Multiple Choice Worth 1 points) (09.03 MC) What is the formula for the total distance traveled by a particle from ( = 0 to ( = 4 given the position s(1) = ( 1+ 5.-1p)? D NF + 12 + 21 + 1 0 0 ( V1+ 21 + 2 14 at Question 2(Muluple Choice Worth 1 points) (09.03 MC) ^ particle moves according to the position vector s(f) - (sint.cos 2t). Determine when the particle is at rest._ Lessons Assessments Gradebook Email # Tools Question 3(Multiple Choice Worth 1 points) (09.03 MC) At t = 0 a particle is at point (1, -2). Find the position of the particle that moves with velocity vector v(f) = (f-xcost.21 - x sinxt) when t = 3. 0 10 09. 10 (12 5 O Question 4(Multiple Choice Worth 1 points) (09.03 MC) An object moves along a curve in the xy-plane according to the position (e' cost.tan 2/) Find the speed of the object when ? = 1. Round to three decimal 0.911 0 0.912Lessons Assessments Gradebook Email #Tools . Question 4(Multiple Choice Worth 1 points) (09.03 MC) An object moves along a curve in the xy-plane according to the position (e' cost.tan 121) Find the speed of the object when t = 1. Round to three decimal places. 0.911 0.912 O 2.495 O 2.496 Question 5(Multiple Choice Worth 1 points) (09.03 MC) A point moves in a plane such that its position is defined by x = In21 and y = 3 - 15. Find the acceleration vector when [ = 2 2305 16 325 12 MO2.496 Question 5(Multiple Choice Worth 1 points) (09.03 MC) A point moves in a plane such that its position is defined by x = In2t and y = 3 - ~. Find the acceleration vector when t = 2 2305 16 325 10 (* -12 ) 0 (- -12 ) 9 M

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