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Question 3 : [ 1 0 marks: 2 . 5 marks each ] ( Easy but Tricky ) Design F = Pi ( 2

Question 3: [10 marks: 2.5 marks each](Easy but Tricky)
Design F =\Pi (2,4,7,10)+ D(1,6,8,9) using a decoder, NOT gates, and a single gate of:
a. OR
b. NAND
c. AND
d. NOR

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