Question 3 6 pts In a bag of M&M's, there are 90 M&Ms, with 15 red ones, 17 orange ones, 23 blue ones, 8 green ones, 20 yellow ones, and 7 brown ones. They are mixed up so that each candy piece is equally likely to be selected if we pick one. Use the probability rules below when appropriate. Probability Rules . P(A or B) = P(A) + P(B) - P(A and B) . P(not A) = 1 - P(A) . P(A if B) = P(A and B) P(B) . P(Aif B) # P(B if A) a) If we select one at random, the probability that it is not orange. P(not orange) = (round the answer to 3 decimal places) b) If we select one at random, the probability that it is blue or yellow. P(blue or yellow) = (round the answer to 3 decimal places) c) If we select one, put it back, and then select a second one, what is the probability that the first one is red and the second one is green? P(first one red and second one is green) = round the answer to 4 decimal places)