Question 3 (Essay Worth 15 points) (02.06 HC) Let y = 2(x - 5)2 - 6. Part A: Is the given relation a function? Is it one-to-one? Explain completely. If it is not one-to-one, determine a possible restriction on the domain such that the relation is one- to-one. (5 points) Part B: Determine y . Show all necessary calculations. (5 points) Part C: Prove algebraically that y and y are inverse functions. (5 points) 9 Source V C BIUSXX IX Styles Format |Font Size - A- A