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Question 3(4 points) Consider convergent series n=2 a n {version:1.1,math:(sum_{n=2}^infty a_n)}, where a n =1 n(lnn) 4 {version:1.1,math:(frac {1}{n(ln{n})^4})}.Given that S 10 =S 9 =

Question 3(4 points)

Consider convergent series

n=2

a

n

{"version":"1.1","math":"\(\sum_{n=2}^\infty a_n\)"}, wherean=1

n(lnn)

4

{"version":"1.1","math":"\(\frac {1}{n(\ln{n})^4}\)"}.Given thatS10=S

9

=

9

n=2

a

n

{"version":"1.1","math":"\(S_{9}=\sum_{n=2}^{9} a_n\)"}2.5300, find a better approximation of the sumSof this series by estimating the errorE9=S

{"version":"1.1","math":"-"}S9.Use four digits after the decimal point in your calculation.

image text in transcribed
Question 3 (4 points) Consider convergent series 2212 am where an = 1 4 . Given that 510 = S9 = 23:2 an >> 2.5300, n(ln n) nd a better approximation of the sum S of this series by estimating the error E9 = S S9 . Use four digits after the decimal point in your calculation. I: a f v Paragraph v B I U v ... Add a File Record Audio Record Video

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