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Question 3(4 points) Consider convergent series n=2 a n {version:1.1,math:(sum_{n=2}^infty a_n)}, where a n =1 n(lnn) 4 {version:1.1,math:(frac {1}{n(ln{n})^4})}.Given that S 10 =S 9 =
Question 3(4 points)
Consider convergent series
n=2
a
n
{"version":"1.1","math":"\(\sum_{n=2}^\infty a_n\)"}, wherean=1
n(lnn)
4
{"version":"1.1","math":"\(\frac {1}{n(\ln{n})^4}\)"}.Given thatS10=S
9
=
9
n=2
a
n
{"version":"1.1","math":"\(S_{9}=\sum_{n=2}^{9} a_n\)"}2.5300, find a better approximation of the sumSof this series by estimating the errorE9=S
{"version":"1.1","math":""}S9.Use four digits after the decimal point in your calculation.
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