Question $4$

$1pts$

Oxygen at $150K$ and $41\mathrm{.}64$atm has a tabulated specific volume of $4\mathrm{.}684c\frac{m^3}{g}$ and a specific internal energy of $1706\frac{J}{m}ol.$ The specific enthalpy of $O_2$ in this state is $\_,\frac{\text{I}}{m}ol.$

Hint:Convert specific volume to $\frac{L}{m}ol$ using molecular weight of oxygen as $32$ and $1L=1000c{m}^3.$ Then use the definition of $H=U+PV.$ A useful conversion is $1$atm$=101\mathrm{.}3161\frac{J}{L}.$

$3450$

$2340$

$1230$

$1890$