Question: A disk of radius 0.2 m can rotate horizontally about a fixed vertical axis that goes through its center of mass. Its moment of

A disk of radius 0.2 m can rotate horizontally about a fixed vertical axis that goes through its center of mass. Its moment of inertia relative to this axis is 5.0 kg.m. Assume no air friction. (a) The initial angular velocity of the disk is 20 rad s. It comes to rest after 10 s. While the disk is rotating, friction in the rotation axis exerts a constant torque r. Determine the value of r. Next (with friction still acting), a horizontal force of constant magnitude 100 N constantly acts tangentially at a point on the rim of the disk causing it to rotate counterclockwise from rest. (b) Calculate the magnitude of the torque due to the 100 N force. (c) Calculate the angular acceleration of the disk. (d) For an angular displacement of the disk of 3.0 rad, calculate the net work done on the disk. (e) How much rotational kinetic energy is gained by the disk for the angular displacement of 3.0 rad?
Step by Step Solution
3.46 Rating (156 Votes )
There are 3 Steps involved in it
Lets go through each part step by step a Determine the value of tau frictional torque 1 Given Data I... View full answer
Get step-by-step solutions from verified subject matter experts
