Answered step by step
Verified Expert Solution
Question
1 Approved Answer
Question #4 A force of 516 N is required to just get a mass of 75 kg moving along a horizontal surface. While a force
Question #4 A force of 516 N is required to just get a mass of 75 kg moving along a horizontal surface. While a force of 630 N cause the mass to accelerate at 6 m/s-. a. Calculate the coefficient of static friction b. Calculate the coefficient of kinetic friction 2- An 85 kg skydiver is jumping from an airplane. If the magnitude of the air resistance acting of the skydiver is constant and equals to 493 N [upward], Find a. the acceleration of the skydiver 5 seconds later. b. the distance moved in the 5 secondsQuestion #6 A string is tied to a 5.2Kg block and a 350g hanging bucket, as shown below. Students add 20g washers one at a time to the bucket. The students are unaware that the coefficient of static friction for the block on the table is 0.45. Draw FBD for each object. a. What is the maximum force of static friction for the block? b. How many washers can the students add to the bucket without moving the block? c. The coefficient of kinetic friction is 0.32. Calculate the acceleration of the system when the final washer is placed in the bucket and the object starts to move. 5.2 Kg 350 gQuestion #5 A person is pulling a box of mass 30 kg across a floor with ( u, =0.45 and u, = 0.35 ) between the box and the floor. 1. Find the applied force by the person to put the box in motion if: a. The force applied horizontally b. The force applied at 370 above horizontal (Draw FBD) 2. Find the applied force by the person to accelerate the box by 5m/s: c. The force applied horizontally d. The force applied at 370 above horizontal e. The force applied at 370 below horizontalQuestion #2 The gravity on the surface of Mars is 3.7 m/s'. For a student of weight 637 N on Earth: a. What is the exact Acceleration on the surface of Earth? b. What is his mass on earth? c. What would be his mass on Mars d. What would be his weight on Mars? e. What would be his weight on the moon (g = 1.6 m/s-)
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started