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A 2.45-Mev neutron is elastically scattered through an angle of 41 degrees in a collision with a He nucleus. What is the actual change

A 2.45-Mev neutron is elastically scattered through an angle of 41 degrees in a collision with a "He nucleus. What is the actual change in lethargy for this neutron that scatters off of the Helium-4 nucleus? Use three decimal places in your answer.

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