Question $6$ and $7$ have common data

Turbulent velocity profile in a non$-$ideal tubular reactor is given by

$u=u_m(1-\frac{r}{R}{)}^{0\mathrm{.}14}$

The specific reaction rate is $0\mathrm{.}1s^{-1},$ the centre$-$line velocity $(u_m)$ is $1\frac{m}{s},$ and the reactor length is $10m$ and $R=1m.$

$2$ points

The correct expression of the $E$ curve is

$E(t)=3\mathrm{.}4\frac{{}^8}{t^9}(1-(0\mathrm{.}82\frac{}{t}{)}^{\frac{1}{7}})$

$E(t)=3\mathrm{.}4\frac{{}^9}{t^8}(1-(0\mathrm{.}82\frac{t}{}{)}^7)$

$E(t)=3\mathrm{.}4\frac{{}^8}{t^9}(1-(0\mathrm{.}82\frac{}{t}{)}^7)$

$E(t)=3\mathrm{.}4\frac{{}^9}{t^8}(1-(0\mathrm{.}82\frac{t}{}{)}^{\frac{1}{7}})$

$2$ points

If an elementary isomerization occurs in this reactor, the conversion at the reactor outlet would be

$20\%$

$50\%$

$70\%$

$90\%$