Question 7 A psychologist is interested in constructing a 99% confidence interval for the proportion of people who accept the theory that a person's spirit is no more than the complicated network of neurons in the brain. Of those randomly selected, 62 of the 821 people agreed with this theory. a. With 99% confidence the proportion of all people who accept the theory that a person's spirit is no more than the complicated network of neurons in the brain is between and Round to 3 decimal places. b. If many groups of 821 randomly selected people are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of all people who accept the theory that a person's spirit is no more than the complicated network of neurons in the brain and about percent will not contain the true population proportion. Question 8 > Out of 600 people sampled, 180 had kids. Assuming the conditions are met, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places Question 9 If n = 500 and p (p-hat) = 0.55, construct a 99% confidence interval. Give your answers to three decimals . Question 10 If n=470 and p (p-hat) = 0.66, construct a 99% confidence interval. Give your answers to three decimals. Question 11 If n = 510 and p (p-hat) =0.28, find the margin of error at a 90% confidence level. Round to 4 places.. Question 12 In a recent poll, 520 people were asked if they liked dogs, and 63% said they did. Find the margin of error of this poll, at the 95% confidence level. Give your answer to three decimals Question 13 6.18 Is college worth it? Part II: Exercise 6.16 presents the results of a poll where 48% of 331 Americans who decide to not go to college do so because they cannot afford it. (a) Calculate a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context. lower bound: (please round to four decimal places) upper bound: (please round to four decimal places) Interpret the confidence interval in context: O 90% of Americans choose not to go to college because they cannot afford it O We can be 90% confident that our confidence interval contains the sample proportion of Americans who choose not to go to college because they cannot afford it O We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval (b) Suppose we wanted the margin of error for the 90% confidence level to be about 1.5%. How large of a survey would you recommend? A survey should include at least people. * Question 14 Score on last try: 0 of 1 pts. See Details for more. > Next question You can retry this question below You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proportion is approximately 61%. You would like to be 93% confident that your estimate is within 5% of the true population proportion. How large of a sample size is required? Please round your z* value to 3 decimal places to use in your calculation. nQuestion 15 A political candidate has asked you to conduct a poll to determine what percentage of people support her, assume p=.5. If the candidate only wants a 6% margin of error at a 90% confidence level, what size of sample is needed