Question 9 0/1 pt 9 3 2 19 0 Details You have 47 yards of fencing and you need to enclose a rectangular area having TWO pens as shown. However, a wall is on one side of the rectangle so you do NOT need fencing on that side. You desire to enclose the largest possible area. Wall x a) Given x is the dimension of one side of the rectangle, enter an expression for the other dimension of the rectangle. Your answer should have an "x" in it. Also select appropriate units. other dimension = O yards square yards b) Find an expression for the area of the rectangle only in terms of x. Check the appropriate units. area = O yards square yards c) What are the dimensions of the rectangle with the largest enclosed area. Enter your dimensions as a list of numbers separated by a comma. dimensions are O yards square yards d) What is the largest area you can enclose in a rectangle using 47 yards of fencing? largest area = O yards square yards Submit QuestionQuestion 10 0/1 pt 3 19 0 Details You have 18 feet of wire to enclose 3 sides of a garden. One side is a wall Wall (no fence needed) that needs no fence. The vertical sides (labeled x) each require 6 strands of wire. The horizontal side (labeled y) requires 3 strands of wire. X garden IX What values for x and y will create a fence that encloses the maximum area of garden? X = y = Enter each answer as a whole number or as a reduced fraction (such as 4/5, 35/4 or 11/2). Submit QuestionQuestion 11 0/1 pt 9 3 19 0 Details You have 42 feet of wire to enclose 2 sides of a garden. Two sides are against Wall (no fence needed) walls so they need no fence. The vertical side (labeled x) requires 4 strands of wire. The horizontal side (labeled y) requires 3 strands of wire. X garden What values for x and y will create a fence that encloses the maximum area of garden? y X = y = Enter each answer as a whole number or as a reduced fraction (such as 4/5, 35/4 or 11/2). Submit QuestionQ-10 lex 3y P= QX (2) + 3y 10 = 12 x + 34 18-12x = 10 x -12x thy 34 = 18-12x 3 3 y = 6-4x A = xy A = X ( 4- 4 x ) A-x - 4X 2 ACX ) = COX - 4x A' (x ) = Q(1 ) - 2(4) (x ) A' ( x ) = 4 - 8 x A' (x ) = 0 0 = 6-B X 8x = 6 X = feet y = 4- 4x = 6- 4 (3 3 feet CS Scanned with CamScanner