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Question are listed below Exercise 1 (2+2+2+2+2 pts). Joint distribution of discrete random variables. The joint probability mass function of the random variables (X, Y)

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Exercise 1 (2+2+2+2+2 pts). Joint distribution of discrete random variables. The joint probability mass function of the random variables (X, Y) is given by the following table: Y = 0 Y=1 Y=2 X =0 1/18 2/18 3/18 X =1 3/18 2/18 1/18 X = 2 1/9 1/9 1/9 1. What is P(Y

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