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QUESTION Assuming short-circuit evaluation for && and II, hand translate the following pseudo-code function into three-address code int leap(int y) { if(y%4 != 0 ||

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QUESTION Assuming short-circuit evaluation for && and II, hand translate the following pseudo-code function into three-address code int leap(int y) { if(y%4 != 0 || ( %100 == 0 && y%400 - 0)) { return 0; } else { return 1; } }

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