Question: Ethylene is formed by ethane cracking via the following reversible reaction with a pure ethane feed: C2H6C2H4+H2 (a) Given the following equilibrium constants: K400C=0.000521K500C=0.0204 What would be the equilibrium conversion at 650C and 1 bar pressure? Assume all gases behave ideally. (b) An alternative dehydrogenation pathway is possible: C2H6+21O2C2H4+H2O with the following equilibrium constants: K400C=1.161026K500C=5.341023 Why do you think this alternative reaction pathway is not more commonly used