Question
Questions : 1 A woodcutter has to cut 100 fence posts of a standard length and he has a metal bar of the required length
Questions :
1 A woodcutter has to cut 100 fence posts of a standard length and he has a metal bar of
the required length to act as the standard. The woodcutter decides to vary his
procedure from post to post he cuts the first post using the metal standard, then uses
this post as his standard for the cut of the next post. He continues in a similar manner,
each time using the most recently cut post as the standard for the next cut.
Each time the woodcutter cuts a post there is an error in the length cut relative to the
standard being employed for that cut you should assume that the errors are
independent observations of a random variable with mean 0 and standard deviation
3mm.
Calculate, approximately, the probability that the length of the final post differs from
the length of the original metal standard by more than 15mm.
[5]
2 A researcher wishes to investigate whether a coin is balanced or not, that is if
P heads ( ) 0.5 = . She throws the coin four times and decides to accept the hypothesis
0 H P heads : ( ) 0.5 = in a test against the alternative 1 H P heads : ( ) 0.5 , if the number
of times that the coin lands "heads" is 1, 2, or 3.
(i) Calculate the probability of the type I error of this test. [3]
(ii) Calculate the probability of the type II error of this test, if the true probability
that the coin lands "heads" is 0.7. [3]
[Total 6]
3 Pressure readings are taken regularly from a meter. It transpires that, in a random
sample of 100 such readings, 45 are less than 1, 35 are between 1 and 2, and 20 are
between 2 and 3.
Perform a 2
goodness of fit test of the model that states that the readings are
independent observations of a random variable that is uniformly distributed on (0, 3).
[5] CT3 A20085 PLEASE TURN OVER
4 In an investigation about the duration of insurance policies of a certain type, a sample
of n policies is studied. All n policies have been initiated at the same time, which is
also the time of the start of the investigation. For each policy, the time T (in months)
until the policy expires can be modelled as an exponential random variable with
parameter , independently of the times for all other policies.
(i) Suppose that the investigation is terminated as soon as k policies have expired,
where k is a known (predetermined) constant. The observed policy expiry
times are denoted by t1, t2, ..., tk with 0 < k n and t1< t2 <... < tk.
(a) Show that the probability that any randomly selected policy is still in
force at the time of the termination of the investigation is kt
e
.
(b) Show that the likelihood function of the parameter , using information
from all n policies, is given by
1 ( ) ( )
k
i
i k
t
k nk t L ee =
= .
Hence find the maximum likelihood estimate (MLE) of .
(c) Consider an investigation on 20 policies which is terminated when five
policies have expired, giving the following observed expiry times (in
months):
1.03 6.67 12.70 12.88 21.54
Calculate the MLE of based on this sample.
[9]
(ii) Suppose instead that the investigation is terminated after a fixed length of time
t0. The number of policies that have expired by time t0 is considered to be a
random variable, denoted by K.
(a) Explain clearly why the distribution of K is binomial and determine its
parameters.
(b) Hence find the MLE of in this case.
(c) Consider an investigation on 20 policies that is terminated after 24
months. By the time of termination five policies have expired.
Use this information to calculate the MLE of in this case.
[9]
[Total 18] CT3 A20086
5 The members of the computer games clubs of three neighbouring schools decide to
take part in a light-hearted competition. Each club selects five of its members at
random under a procedure agreed and supervised by the clubs. Each selected student
then plays a particular game at the end of which the score he/she has attained is
displayed and recorded - the standard set by the games designers is such that
reasonably competent players should score about 100.
The results are as follows:
School 1 105 134 96 147 116
School 2 103 81 91 100 110
School 3 137 115 105 123 149
(i) An analysis of variance is conducted on these results and gives the following
ANOVA table:
Source of variation d.f. SS MSS
Between schools 2 2,298 1,149
Residual 12 3,468 289
Total 14 5,766
(a) Test the hypothesis that there are no school effects against a general
alternative.
You should quote a narrow range of values within which the
probability-value of the data lies, and state your conclusion clearly.
(b) Calculate a 95% confidence interval for the underlying mean score for
club members in School 1, using the information available from all
three schools.
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