Questions 17 - 20.A claims adjustment manager learns that her 200 employees (N = 200) spend an average of 6 hours per claims case with a standard deviation of 2 hours.The numbers of hours are normally distributed.

17.We want to answer the following question:What is the probability of finding an employee who spends more than 12hours per claims case?So we first calculate the z score that corresponds to12.What is that z score?

Note:This answer requires an exact answer and no partial credit will be given.The answer must be a one digit whole number (no decimals).

Z ScoreAnswer =___________

18.What is theprobabilityof finding an employee who spends more than 12 hours per claims case?

_________________

Note: this answer requires a number that has four digits after the decimal. For example: .0234, or 0.0234. No partial credit will be given if the answer does not conform to this format.

Probability Answer =_______________

19.How many employeesspend more than 8 hours per claims case?

Hint: In order to get the number of cases, we take a three step process. We get the z score that corresponds to 8 hours, obtain the probability that goes with that z score, and then multiply the obtained probability by the total number of cases. The total number of cases is 200.Z = (Specific Score-Mean)/Standard Deviation. Z= (8-6)/2 = 1.

Number of Employees Answer =

A. 31.74

B. 19.10

C. 158.76

D. 58.99

20.What is the probability of finding an employee who spends less than 4 hours per claims case? The answer to this question has four digits after the decimal. For example: .9999, or 0.9999. The exact number is required and no partial credit will be given if the answer does not conform to this format.

Hint: We need to take a two step process. First we calculate the z score that goes with 4, using the formula: (specific score - mean)/standard deviation. (4-6)/2 = -2/2 = -1.

Answer:_____________