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A delicate acidification of a reagent solution is necessary as a part of a bioprocess. The following conditions are relevant: . r = 0.10 L/s (that is, liters per second). . G = 1.0 x 104 mol/L hydrogen ions (pH = 4 = -log0(c)), where "mol" - that is "moles" - is a very commonly used unit for the amount of some chemical. V(0) = 50 L, the initial volume at t = 0. x(0) = 1.0 x107 mol/L * V(0) L = 5.0 x 10 mol hydrogen ions (the starting pH = 7 = -log0(1.0 x10-)), in the reaction tank. r = 0.02 L/s, (for continuous monitoring). To solve this problem: Assuming constant, effective mixing of the chemicals in the tank, write a differential equation for the change in the amount (in moles) of hydrogen ions in the tank per unit time (in seconds), given the information above. (Ignore any buffering capacity of the solution.) Find the particular solution of the differential equation for the initial conditions given above. Assume the flows will be stopped when the volume of the tank reaches 83 L. How many seconds since t = 0 will this be? At this time and solution volume (in the tank), how many moles of hydrogen ions will be in tank? Optionally, you may convert this value to pH, too.