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R = 0.0821 L'atm mol- K- = 8.314 kgm/s.mol-K- 1 atm = 760.0 mm Hg = 76.0 cm Hg = 760.0 torr = 1.013 x
R = 0.0821 L'atm mol- K- = 8.314 kgm/s.mol-K- 1 atm = 760.0 mm Hg = 76.0 cm Hg = 760.0 torr = 1.013 x 105 Pa = 101.3 kPa = 14.7 psi 1. If 50.75 g of O2 occupies 13.0 L at STP, 129.3 g of the same gas will occupy A. 5.10 B. 6.60 C. 16.8 D. 33.1 Answer: L at STP
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Biochemistry Concepts and Connections
Authors: Dean R. Appling, Spencer J. Anthony Cahill, Christopher K. Mathews
1st edition
