R = 8.314 J/mol-K= 0.08206 atm-L/mol-K lu = 1.6605 x 10-27kg latm = 101.3 kPa ; 1m' = 1000L; 1L = 1000cm' STP = 0'C, latm ; 0.C = 273.15K 1 atm-L = 101.3J KB = 1.3806x10-23 J/K NA = 6.022 x1023molecules/mole 1AU = 149.6 x 10km Y = Cp / Cv 6 = 5.67 x 10-8W/m2-K411. 2.50 moles of a diatomic ideal gas undergoes a Carnot heat engine cycle "ABCDA" where PA = 7.60atm and TA = TB = 425.C and To= TD = 225 C. Isothermal expansion A->B doubles the volume from A to B. Thus, A->B is isothermal, B->C is adiabatic, C->D is isothermal, D->A is adiabatic. a) Find volumes (in L) at A, B, C and D. c) Find Wout and cycle efficiency. d) If the engine runs at exactly 2400rpm find the power output (in kW). b) Find QH , Qc e) If the process were reversed to make a refrigerator, find the COP and the Win per cycle