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Why is the angle the same for part a and b in this problem, but in the problem, below it is different for part a and b? Please explain it to me like I'm 5 :) so I can better understand. For problem 5 you'll see that for part A the angle is 35 but for part B its 145. This differs however for problem 3 which has it both as 130 degrees.

Problem 5 E = 100N/C An electric dipole is placed in an electric field as shown in - 3x10-5CO- the picture on the right hand side where you can find all the pertinent information you may need. 1 = 10-m 1450 1 350 a) What are magnitude and direction of the torque on the + 3x10-5C electric dipole? In the picture, clearly draw and label the vector representing the torque. P = q1 = 10-5m 3 x 10-5C = 3x 10-10C . m 171 = PXE = |P| |E sin (0) = 3x 10-10C. m 100- sin (35') = 1.72 x 10-8N . m O out of the page! b) What is the electric potential energy of the electric dipole? U = - P . E = - P |E cos (0) U = - 3x 10-10C . m 100 - cos (145.) = 2.46 x 10-8JProblem 3 130=180-50 E = 600N/C An electric dipole is placed in an electric field as shown +2x10-6C in the picture where you can find all the pertinent information you may need. we-01 = 50 - 2x10-6C a) What are magnitude and direction of the torque on the electric dipole? In the picture, clearly draw and label the vector representing the torque. |7| = PXE = |p| |E sin (0) = 91|E sin (0) = 2 x 10-C x 10 5m x 600 - sin (180 - 50.) = 9.193 x 10 9N . m & into the page b) What is the electric potential energy of the electric dipole? U = - P . E = - P| |E cos (0) U= - 2x 10-C x 10 5m x 600- cos ( 180 - 50 ) = + 7.713 x 10-9J 60