Question
Real life case study Cucumber is a winter cash crop, which is cultivated in the Kingdom of Bahrain. The fruit is popular and used in
Real life case study Cucumber is a winter cash crop, which is cultivated in the Kingdom of Bahrain. The fruit is popular and used in fresh salads and juices and consumed almost on daily bases by many families. Accordingly, it can be a good source of income for the farmers. In Bahrain, cucumber seedlings are established during September by seed germination. Farmers grow the seedlings to maturity and fruiting stage in controlled greenhouses. Unfortunately, only few farmers use hydroponic systems in Bahrain. Hydroponic systems proved to be an excellent alternative method for mass crop production with minimal water consumption. However, the majority of our farmers are not trained on using these systems, which can affect their crop production and hence their income. Here we have an example: Kareem and Mohammed are two Bahraini farmers who grow cucumber plants as a cash crop. Frequently and for more than two seasons, Mohammeds yield was double Kareems Yield. Therefore, Kareems income is half of Mohammeds income from the same crop using the same hydroponic systems. You are an agricultural consultant. Kareem asked you for help to overcome the problem of low crop production. You visited Kareems farm and did some experiments and collected data, which are presented in the attached excel sheet. Based on what you have learned in BIOLS 320 laboratory and theory sessions, analyze and solve Kareems problem of low crop production. Find the reason(s) and the solution(s) for the problem(s) you have identified.
Using the data you have collected as a consultant and provided in the attached excel sheet, precisely identify the cause(s) of the problem of low crop production by Kareem.
Please help me verify my account and find problems
Seedling Fresh wight (g) Mohammed's Farm Kareems Farm 68 32 75 29 79 35 80 25 1 2 3 4 5 Kareem's Farm Nutrient solution: 1- Concentration of Total nutrients = 6M 2- Greenhouse temperature = 210C solute potential Nutrient solution:)=-RTCs=-0.0083143*(21+273)*6 solute potential= -14.6664252 MPa Pressure potential=0 MPa water potential=solute potential+Pressure potential water potential=-14.666+0=-14.666 6 7 8 9 10 11 Concentration of Solution (M) change % Change in weight 12 13 0 Leaves initial weight (g) 0.85 0.88 0.86 Leaves Final Weight (g) 0.93 0.82 0.71 0.08 14 0.5 -0.06 15 1 -0.15 -0.28 16 0.9 17 9.412 -6.818 -17.442 -31.111 -37.209 -48.810 -64.368 -72.727 1.5 2 2.5 3 3.5 18 0.62 0.54 0.43 0.31 0.24 0.86 0.84 0.87 0.88 -0.32 -0.41 -0.56 -0.64 19 20 21 22 % Change in weight VS Concentration of Solution (M) 23 20 24 25 10 10 26 27 0 0.5 1.5 2.5 3.5 28 - 10 29 30 -20 31 32 % Change in weight 33 -40 34 35 -50 36 -60 37 38 -70 39 40 80 Concentration of Solution (M) 41 42 43 The pH of the nutrient solution used in Kareems Farm = 5.7 5 A B D E F G . The Readings Irom Mareem srarm Leaves Replicates Fresh weight Total volume of acetone used A 663 A 646 A 470 A 750 A Old Leaves 2 0.004 0.002 0.001 3 0.40 0.40 0.40 0.40 0.40 0.40 Avarage 15ml 0.002 0.203 0.207 0.230 0.213 0.498 0.497 0.593 0.529 0.125 0.189 0.155 0.156 0.275 0.285 0.319 0.293 0.445 0.592 0.542 0.529 0.528 0.537 0.626 0.564 0.003 New Leaves 2 3 040 0.004 0.006 0.004 Avarage 040 Leaves Replicates A 646 A 470 A 750 1 2 The Readings from Mohammed's Farm Total volume of acetone Fresh weight A 663 used 0.40 0.456 0.40 0.514 0.40 0.445 0.40 15ml 0.472 0.40 0.501 0.40 0.497 0.273 0.300 0.004 0.002 Old Leaves 3 0.445 0.592 0.542 0.529 0.528 0.537 0.298 0.220 0.275 0.285 Avarage 1 2 0.001 0.002 0.003 0.004 New Leaves chl b chl b Kareem's Farm chla Old Leave 80.372 New Leav 207.497 Mohammed's Farm chla Old Leave 184.566 New Leav 195.408 total chlon cartenoid 156.804 50.298 328.647 34.637 76.432 118.816 128.643 total chlon cartenoid 313.209 82.735 320.166 88.041 124.758 Chla Chla 250.000 200.000 150.000 198.000 196.000 194.000 192.000 1000 190.000 100 188.000 186.000 1950 1940 184.000 182.000 180.000 178.000 100.000 50.000 0.000 Old Leaves New Leaves Old Leaves New Leaves Chlb Chlb 140.000 129.000 120.000 128.000 100.000 127.000 80.000 126.000 60.000 125.000 40.000 124.000 20.000 123.000 0.000 122.000 Old Leaves New Leaves Old Leaves New Leaves total chlorophyll total chlorophyll 322.000 350.000 320.000 300.000 318.000 250.000 316.000 200.000 150.000 314.000 100.000 312.000 310.000 308.000 50.000 O: 0.000 Old Leaves New Leaves Old Leaves New Leaves cartenoid cartenoid 89.000 88.000 60.000 50.000 87.000 86.000 85.000 40.000 30.000 84.000 83.000 82.000 81.000 20.000 10.000 80.000 0.000 Old Leaves New Leaves Old Leaves New Leaves Pooled Variance Hypothesized Mean Difference df t Stat P(TStep by Step Solution
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