Recall that if the monic quadratic equation z + sz + r = 0 has roots (or zeroes) wj and w2, then we can write 2 2 + sz t r = (2 - w1 ) (z - W2). By comparing the coefficients of z on both sides, it follows that w1 + w2 = -S WJW2 = r So: i) The sum of the roots of Z - 3 z + 6 = 0 is 3 while the product of the roots is 6 ii) The monic quadratic equation, in z, with complex conjugate roots 4 + 5 i and 4 - 5 i must be 0 = iii) The monic quadratic equation, in z, with complex conjugate roots -1 + 3 i and -1 - 3 i must be 0 =