Recall that in the Sally Clark court case we discussed in class, it was pointed out that the rate of SIDS (Sudden Infant Death Syndrome) in the general population was 1/8,500. What is the right way to think about the probability that two children in a single household die of SIDS? Question 1 options: The probability that two children die of SIDS in a single household is not possible to calculate without additional knowledge on whether factors that contribute to SIDS can be shared within a household The probability that two children die of SIDS in a single household is 2*(1/8500) = 1/4,250 The probability that two children die of SIDS in a single household is (1/8500)^2 = 1/72,250,00